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3 years ago

34g aluminum are combined with 39g chlorine gas which is the limiting reactant

Chemistry

1 answer:

vampirchik [111]3 years ago

6 0

The limiting reactant is chlorine (Cl2).

<u>Explanation</u>:

Limiting reactant is the amount of product formed which gets limited by the reagent without continuing it.

2 Al + 3 Cl2 ==> 2 AlCl3 represents the balanced equation.

Number of moles Al present = 34 g Al x 1 mole Al / 26.98 g

= 1.260 g moles of Al

Number of moles Cl2 present = 39 g Cl2 x 1 mole Cl2 / 35.45 g

= 1.10 g moles of Cl2

Dividing each reactant by it's coefficient in the balanced equation obtains:

1.260 moles Al / 2 = 0.63 g moles of Al

1.11 moles Cl2 / 3 = 0.36 g moles of Cl2

The reactant which produces a lesser amount of product is called as limiting reactant.

Here the Limiting reactant is Cl2.

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What does the 32.06 represent?

lana [24]

The 32.06 represent The atomic mass, the average number of protons & neutrons

<h3>Further explanation </h3>

The Atomic Number (Z) indicates the number of protons in an atom of an element. If the atom is neutral then the number of protons will be equal to the number of electrons. So the atomic number can also indicate the number of electrons.

So atomic number = number of protons = number of electrons

Mass Number (A) is the sum of protons and neutrons

Mass Number (A) = Number of protons + Number of Neutrons

So that the relationship between atomic numbers and mass numbers can be formulated as follows:

Atomic Number (Z) = Mass Number (A) - Number of Neutrons

In the following element notation,

$\large {{{Z} \atop {A}} \right X}$

X = symbol of elemental atom

A = mass number

= number of protons + number of neutrons

Z = atomic number

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4 0

3 years ago

You need to make an aqueous solution of 0.182 M aluminum sulfate for an experiment in lab, using a 250 mL volumetric flask. How

Ksju [112]

Answer:

Hence, 15.99 g of solid Aluminum Sulfate should be added in 250 mL of Volumetric flask.

Explanation:

To make 0.187 M of Aluminum Sulfate solution in a 250 mL (0.250 L) Volumetric flask

The molar mass of Aluminum Sulfate = 342.15 g/mol

Using the molarity formula:-

Molarity = Number of moles/Volume of solution in a liter

Number of moles = Given weight/ molar mass

Molarity = (Given weight/ molar mass)/Volume of solution in liter

0.187 M = (Given weight/342.15 g/mol)/0.250 L

Given weight = 15.99 g

8 0

3 years ago

A chemical engineer is studying the two reactions shown in the table below.

Kamila [148]

Explanation:

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2 years ago

What fraction of the original atoms of the radioactive sample will remain after the given number of half-lives has passed?

meriva

Answer:

1/8

Explanation:

$\frac{1}{ {2}^{3} } = \frac{1}{8}$

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2 years ago

Show, in a step by step fashion, your calculations to determine the percent

marusya05 [52]

The percent by volume of a solution : 19.23%

<h3>Further explanation</h3>

Given

50 ml of ethanol

210 ml of water

Required

The percent by volume of a solution

Solution

Percent Volume (% v/v) : volume (ml) of solute/100 ml of solution ⇒ ratio of the volume of the solute to total volume of the solution

$\tt \%solute(v/v)=\dfrac{solute~volume}{solution~volume}\times 100\%$

solute= Ethanol

solvent=water

Solution = solute+solvent

Total volume of the solution :

$\tt =volume~of~Ethanol+solume~of~water\\\\=50~ml+210~ml\\\\=260~ml$

Percent by volume :

$\tt \%volume=\dfrac{50}{260}\times 100\%\\\\\%volume=19.23\%$

8 0

3 years ago