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sweet-ann [11.9K]
3 years ago
5

Draw a isosceles triangle ABC in which AB=AC=6cm and BC=5cm. Construct a triangle PQR similar to triangle ABC in which PQ=8cm. A

lso justify the construction

Mathematics
1 answer:
xenn [34]3 years ago
5 0

Answer:

See the diagram

Step-by-step explanation:

ABC \cong PQR\\\Rightarrow \frac{PQ}{AB} =\frac{PR}{AC}=\frac{QR}{BC} \\\frac{PQ}{AB}=\frac{PR}{AC}\\  \\Since  \ AB=AC\\PQ=PR\\PR=8cm\\\\\frac{PQ}{AB}=\frac{QR}{BC}\\\\QR=\frac{PQ}{AB} \cdot BC\\\\QR=\frac{8}{6} \cdot 5\\\\QR=\frac{20}{3}

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lara [203]

Hello from MrBillDoesMath!

Answer:

Top line: y = (2/3)x + 2

Bottom line:  y = (2/3)x  -1

Discussion:

The graph provided is hard to read but I did the best I could.

The top line appears to pass through the points (0,2) and (-3,0)

For this line

m =  change y /change x = (0-2)/(-3-0) = -2/-3 = +2/3. So

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2 = (2/3) 0 + b   => b = 2

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The bottom line appears to pass through the points (0,-1) and (3,1)

For this line

m =  change y /change x = (1-(-1)) /(3-0) = +2/-3. So

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