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Kaylis [27]
2 years ago
10

NEED ANSWER ASAP PLEASE!!!!!!!

Physics
1 answer:
Usimov [2.4K]2 years ago
7 0

In both questions, the objects are falling from rest so their final velocities after time t will be given by

v_f=v_i+at=at

where a is the acceleration due to gravity given. Note that I take the downward direction to be positive.

23.

v_f=\left(9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)(7\,\mathrm s)\implies v_f=68.6\,\dfrac{\mathrm m}{\mathrm s}

24.

49\,\dfrac{\mathrm m}{\mathrm s}=\left(9.8\,\dfrac{\mathrm m}{\mathrm s^2}\right)t\implies t=5.0\,\mathrm s

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Two airplanes leave an airport at the same time. The velocity of the first airplane is 730 m/h at a heading of 65.3 ◦ . The velo
yanalaym [24]

Answer:

Plane will 741.6959 m apart after 1.7 hour                    

Explanation:

We have given time = 1.7 hr

So if we draw the vectors of a 2d graph we see that the difference in angles is   = 102^{\circ}-65.3^{\circ}=36.7^{\circ}

Speed of first plane  = 730 m/h

So distance traveled by first plane = 730×1.7 = 1241 m

Speed of second plane = 590 m/hr

So distance traveled by second plane = 590×1.7 = 1003 m

We represent these distances as two sides of the triangle, and the distance between the planes as the side opposing the angle 58.6.

Using the law of cosine, r^2 representing the distance between the planes, we see that:

r^2=1241^2+1003^2-2\times 1003\times 1241cos(36.7)=550112.8295

r = 741.6959 m

3 0
3 years ago
Light of wavelength 476.1 nm falls on two slits spaced 0.29 mm apart. What is the required distance from the slits to the screen
stich3 [128]

Answer:

The distance is D  =  2.6 \ m

Explanation:

From the question we are told that

    The wavelength of the light is  \lambda  =  476.1 \ nm  =  476.1 *10^{-9} \ m

      The  distance between the slit is  d =  0.29 \  mm  =  0.29 *10^{-3} \ m

       The  between the first and second dark fringes is  y =  4.2 \ mm  =  4.2 *10^{-3} \ m

Generally  fringe width is mathematically represented as

       y  =  \frac{\lambda * D }{d}

Where D is the distance of the slit to the screen

   Hence

        D  =  \frac{y *  d}{\lambda }

substituting values

       D  =  \frac{ 4.2 *10^{-3} *   0.29 *10^{-3}}{ 476.1 *10^{-9} }

        D  =  2.6 \ m

7 0
3 years ago
Net force is the sum of all the forces acting on an object. If a spring balance pulls on a body with a force of 10 N, and fricti
julsineya [31]

Answer:

5N

Explanation:

(25 N - 20 N = 5 N)

3 0
3 years ago
Consider the following examples of homeostatic regulation: In response to an increase in plasma K concentrations, secretion of t
TiliK225 [7]

Answer:

Both are examples of negative feedback regulation.

Explanation:

The maintenance of the homeostasis in the body is controlled by the the feedback regulation of the body. Two main types of feedback regulation are positive regulation and negative regulation.

The negative regulation occurs when the final product of the reactions inhibits the further secretion of that product. In the given examples of aldosterone and calcium mechanism, the secretion of aldosterone and calcium decreases as the normal levels are acheived in the body.

Thus, the answer is both are examples of negative feedback regulation.

5 0
3 years ago
When the vectors a→ =8n and b→ =6n find the c
n200080 [17]

Answer:

14 N and 2 N

Explanation:

We have two vectors:

a = 8 N

b = 6 N

When the two vectors are in the same direction, their resultant is simply given by the sum of the magnitudes of the two vectors. Therefore, we will have:

c=a+b=8 + 6 = 14 N

Vice-versa, when the two vectors are in opposite directions, we have to consider one of the two vectors as being negative: therefore, the resultant will be given by the difference between the magnitudes of the two vectors. Therefore, in this case, we will have:

c=a-b=8-6 = 2N

3 0
2 years ago
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