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4 years ago

Define what is boyleâs law?

Physics

1 answer:

lawyer [7]4 years ago

8 0

Answer:

Volume of given mass of gas is inversely proportional to pressure of gas

Explanation:

Boyle's law: It states that the volume of given mass of gas is inversely proportional to the pressure of gas at constant temperature.

Mathematical representation:

Suppose, a gas of mass m

T=Constant temperature

V=Volume of gas

P=Pressure of gas

Then, $V\propto\frac{1}{P}$

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. A magnetic field has a magnitude of 0.078 T and is uniform over a circular surface whose radius is 0.10 m. The field is orient

Dmitriy789 [7]

Answer:

The magnetic flux through surface is $2.22 \times 10^{-3}$ Wb

Explanation:

Given :

Magnitude of magnetic field $B = 0.078$ T

Radius of circle $r = 0.10$ m

Angle between field and surface normal $\theta =$ 25°

From the formula of flux,

$\phi = B.A$

$\phi = BA\cos \theta$

Where $\theta =$ angle between magnetic field line and surface normal, $A =$ area of circular surface.

$A = \pi r^{2}$

$A = 3.14 \times (0.10) ^{2}$

$A = 0.0314$ $m^{2}$

Magnetic flux is given by,

$\phi = 0.078 \times 0.0314 \times \cos 25$

$\phi = 2.22 \times 10^{-3}$ Wb

Therefore, the magnetic flux through surface is $2.22 \times 10^{-3}$ Wb

6 0

4 years ago

Calculate the amount of heat transferred when 710 grams of water warms from an initial temperature of 4.0 ºC to a final temperat

tigry1 [53]

Answer:

Q = 62383.44 Joules

Explanation:

Given that,

Mass of water, m = 710 gm

Initial temperature of water, $T_i=4^{\circ} C$

Final temperature of water, $T_f=25^{\circ} C$

The specific heat capacity of liquid water is, $c=4.184\ J/g\ ^oC$

Heat transferred is given by :

$Q=mc(T_f-T_i)$

$Q=710\times 4.184\times (25-4)$

Q = 62383.44 Joules

So, the amount of heat transferred is 62383.44 Joules. Hence, this is the required solution.

3 0

3 years ago

I'm stuck on question 3. Could anyone please explain it?

sergiy2304 [10]

Peak voltage is 2
period is 40ms
frequency = 1/period = 25Hz

5 0

3 years ago

For which pair of launch angles will two identical projectiles have equal ranges?. A. 19.24°, 80.54°B. 16.42°, 74.58°C. 60.23°,

AlladinOne [14]

The kinematic equations of motion that apply here arey(t)=votsin(θ)−12gt2andx(t)=votcos(θ)Setting y(t)=0 yields 0=votsin(θ)−12gt2. If we solve for t, we obtain, by factoring,t=2vsin(θ)gSubstitute this into our equation for x(t). This yieldsx(t)=2v2cos(θ)sin(θ)gThis is equal to x=v^2sin(2θ)gHence the angles that have identical projectiles are have the same range via substitution in the last equation is C. 60.23°, 29.77°

4 0

3 years ago

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Lena [83]

What picture...? You didn't upload one

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4 years ago

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