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Ierofanga [76]
2 years ago
5

If an object's velocity changes from 25 meters per second to

Physics
2 answers:
damaskus [11]2 years ago
3 0

Answer:

B

Explanation:

the way to get b you have divion each other

11Alexandr11 [23.1K]2 years ago
3 0

Answer:

A

Explanation:

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The voltage across the secondary winding is 10,000 V, and the voltage across the primary winding is 25,000 V. If the primary win
Allisa [31]

<u>Answer</u>

80 coils


<u>Explanation</u>

The turn rule of a transformer says that, the amount of voltage induced in the secondary coil is proportional to the number of coil. It is simplified by the ratio:

N<em>p/</em><em>N</em><em>s  =  </em><em>V</em><em>p/</em><em>V</em><em>s</em>

200/Ns  = 25,000/10,000

200 × 10,000  = 25,000Ns

2,000,000 = 25000Ns

Dividing both sides by 25,000,

Ns = 2,000,000/25,000

       = 80 coils




7 0
3 years ago
Read 2 more answers
Which of the following statements is an accurate description of sound transmission through various mediums?
klio [65]
The answer is D. Sound insulators prevent sound from being transmitted better than elastic solids because sound insulators basically muffle and block the sound waves.

5 0
3 years ago
Read 2 more answers
During a tennis serve, a racket is given an angular acceleration of magnitude 150 rad/s^2. At the top of the serve, the racket h
QveST [7]

Answer:

270 m/s²

Explanation:

Given:

α = 150 rad/s²

ω = 12.0 rad/s

r = 1.30 m

Find:

a

The acceleration will have two components: a radial component and a tangential component.

The tangential component is:

at = αr

at = (150 rad/s²)(1.30 m)

at = 195 m/s²

The radial component is:

ar = v² / r

ar = ω² r

ar = (12.0 rad/s)² (1.30 m)

ar = 187.2 m/s²

So the magnitude of the total acceleration is:

a² = at² + ar²

a² = (195 m/s²)² + (187.2 m/s²)²

a = 270 m/s²

3 0
3 years ago
Kinetic energy of an object is equal to
Arte-miy333 [17]
Choice-'b' says the formula for kinetic energy in words.

     KE = (1/2) · (M) · (S²)
7 0
3 years ago
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A square loop of side 7 cm is placed with the nearest side 2 cm from a long wire carrying a current that varies with time at a c
ioda

Answer:

Explanation:

side of the square loop, a = 7 cm

distance of the nearest side from long wire, r = 2 cm = 0.02 m

di/dt = 9 A/s

Integrate on both the sides

\int _{0}^{i}di =9\int _{0}^{t}dt

i = 9t

(a) The magnetic field due to the current carrying wire at a distance r is given by

B = \frac{\mu_{0}i}{2\pi r}

B = \frac{\mu_{0}\times 9t}{2\pi r}

(b)

Magnetic flux,

\phi=\int B\times a dr

\phi=\int \frac{\mu_{0}\times 9t}{2\pi r}\times a dr

\phi=\frac{\mu_{0}\times 9t\times a}{2\pi}\times ln\left ( \frac{2 + 7}{2} \right )

\phi=\frac{\mu_{0}\times 9t\times 0.07}{2\pi}\times ln(4.5)

\phi = 1.89 \times 10^{-7}t

(c)

R = 3 ohm

e = -\frac{d\phi}{dt}

magnitude of voltage is

e = 1.89 x 10^-7 V

induced current, i = e / R = (1.89 x 10^-7) / 3

i = 6.3 x 10^-8 A

8 0
3 years ago
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