The answer is a dwarf planet. Since it isnt a planet it anymore.
Answer:
a = 0.098 m/s²
Explanation:
The satellite, at any distance from the center of the Earth, is subject to the attractive force due to the Earth, according to the Newton´s Universal Law of gravitation, as follows:
Fg = G*ms*mE / (rse)²
According to Newton´s 2nd Law, neglecting any other force acted upon the satellite, we can write the following equation:
Fg = ms*a = G*ms*mE / (rse)²
⇒ a = G*mE / (rse)² (1)
As the distance between the satellite and the center of the Earth is 10 times the radius of the Earth, replacing this value in (1), we have:
a = G*mE / (10*RE)² = G*mE/(RE)² * (1/100)
but G*mE/(RE)², is just g, the acceleration due to gravity on the surface of the earth, so the gravitational acceleration due to Earth at satellite A, is as follows:
a = g*(1/100) = 0.01*g = 0.098 m/s²
Well, the spring constant is measured using the F=k∆x, where F is the force, k is the constant, and ∆x is the change in position. So if the mass is 1.98, the force (mxg) is 19.4. Thus the spring constant is 19.4/.0478(change in position). This equals 405.86.
By definition we know that the distance is equal to the speed by time
d = v * t
Clearing the time we have
t = d / v
for conservation of energy. we have to for every attempt
mgh = (1/2) mv ^ 2
Clearing the speed
v = Root (2gh)
Then, substituting
t = d / v
t = h / (Root (2gh)
We conclude that the time is the same since it depends on the height of the table to the floor.
Answer:
A. 20 N
Explanation:
Weight of the book = mass × acceleration due to gravity
= 2 × 10
= 20 N
