Answer:
C
Step-by-step explanation:
Noting that
+ (- ) is equivalent to subtraction
- (- ) is equivalent to addition
Given
13 + (- 12) - (- 5)
= 13 - 12 + 5
= 1 + 5
= 6 → C
Answer:
13 =t
Step-by-step explanation:
I think the answer is 13 because he charges $6 per hour + $7 equipment fees.
Answer:
<u>144</u>
Step-by-step explanation:
Ok. I love problems like this.
You just have to find the surface are of each part and add it up!
To find the surface area of a rectangle, you multiple the base and the height. To find the surface area of a triangle, you multiple the base and height, and divide by 2 (because its half of a rectangle).
<u>Left rectangle:</u> 3*ll=33
<u>Middle rectangle:</u> 4*ll=44
<u>Right rectangle:</u> 5*ll=55
<u>Top triangle:</u> 3*4=12
12/2=6
<u>Bottom triangle:</u> 3*4=12
12/2=6
<u>ADD THEM ALL!!!</u> 33+44+55+6+6=<u>144</u>
<u></u>
<u></u>
(Also can I please please please have brainliest? I need it to level up!)
Answer:
a) 10,500 big cats
b) 13,401 big cats
c) 33 years
Step-by-step explanation:
Hi, to answer this question we have to apply an exponential growth function:
A = P (1 + r) t
Where:
p = original population
r = growing rate (decimal form; 5/100= 0.05)
t= years
A = population after t years
Replacing with the values given:
a) At 2005, 1 year passed since 2004 (t=1)
A = 10,000 (1+ 0.05)^1
A = 10,500 big cats
b)
At 2010, 6 years passed since 2004 (2010-2004= 6)
A = 10,000 (1+ 0.05)^6
A = 13,401 big cats
c)
50,000 < 10,000 (1+ 0.05)^t
Solving for t:
50,000/10,000 < 1.05^t
5 < 1.05^t
log 5 < log 1.05^t
log 5 < t ( log 1.05)
log 5 / log 1.05 < t
32.9 years < t
33 years = t
Feel free to ask for more if needed or if you did not understand something.
Clearly, wether we're talking about tiles, plants, pages, e-mails, friend or files, the math won't change! :)
Percentages are just special fractions, since they have denominator 100. So, for example, 64% of 75 is given by
So, you divide the number by 100 and then you multiply by the percentage you want. As a last example, 20% of 70 is
And so on with all the others
