All categories

3 years ago

Help me i really don't understand

Mathematics

1 answer:

finlep [7]3 years ago

4 0

1) 1 dot
2) figure 1 + 3 dots
3) figure 2 + 5 dots
4) figure 3 + 7 dots
5) figure 4 + 9 dots
and keeps going....

The next figure, takes the solution of last figure and add odd number in increasing order.
In this type of problem, find a matter.

You might be interested in

PLS HELPPP I HAVE NO IDEA WHICH ONE IT IS

Ne4ueva [31]

Answer:

2(t) or 2 * t

Step-by-step explanation:

Both of those are multiplying 2 and t, which is also what 2t means.

8 0

3 years ago

9.27 repeating as a fraction

lisabon 2012 [21]

I rounded 9.27 repeating to 9.28 to make it easier to solve. It would be 232/25 as an improper fraction and 9 and 7/25 as a mixed number.

6 0

3 years ago

mrs jacobson asks each group of students to write an expression equivalent to the model shown. which group is incorrect expressi

madreJ [45]

Where is the model. To answer I need the model.

8 0

3 years ago

Graph the line y = kx +1 if it is known that the point M belongs to it: M(1,3)

tigry1 [53]

Answer:

$M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ . Please see attachment below to know the graph of the line.

Step-by-step explanation:

From Analytical Geometry we know that a line is represented by this formula:

$y=k\cdot x + b$

Where:

$x$ - Independent variable, dimensionless.

$y$ - Dependent variable, dimensionless.

$k$ - Slope, dimensionless.

$b$ - y-Intercept, dimensionless.

If we know that $b = 1$ , $x = 1$ and $y = 3$ , then we clear slope and solve the resulting expression:

$k = \frac{y-b}{x}$

$k = \frac{3-1}{1}$

$k = 2$

Then, we conclude that point $M(x,y) = (1,3)$ belongs to the line $y = 2\cdot x +1$ , whose graph is presented below.

3 0

3 years ago

PLEASE SOMEONE HELP I TRULY DO NOT UNDERSTAND

IceJOKER [234]

Hi there!

$\large\boxed{f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} } }$

$f(x) = 9x^{3} - 4$

Find the inverse by replacing f(x) with y and swapping the x and y variables:

$x = 9y^{3} - 4$

Isolate y by adding 4 to both sides:

$x + 4 = 9y^{3}$

Divide both sides by 9:

$\frac{x+4}{9}= y^{3}$

Take the cube root of both sides:

$y = \sqrt[3]{\frac{x+4}{9} }\\\\f^{-1}(x) = \sqrt[3]{\frac{x+4}{9} }$

7 0

3 years ago