Answer:
H20 is a compound
Explanation:
(H2O) is a compound consisting of two hydrogen atoms bonded to an oxygen atom.
Answer:
Mass = 3.84 g
Explanation:
Given data:
Mass of hydrogen sulfide = 2.7 g
Mass of oxygen required = ?
Solution:
Chemical equation:
2H₂S + 3O₂ → 2H₂O + 2SO₂
Number of moles of hydrogen sulfide:
Number of moles = mass/ molar mass
Number of moles = 2.7 g / 34 g/mol
Number of moles = 0.08 mol
Now we will compare the moles of hydrogen sulfide with oxygen.
H₂S : O₂
2 : 3
0.08 : 3/2 ×0.08 = 0.12 mol
Mass of oxygen;
Mass = number of moles × molar mass
Mass = 0.12 mol × 32 g/mol
Mass = 3.84 g
Answer:
23.2 mols
Explanation:
(23.2 mol H2)(2 mol H2O) /(2 mol H2) = 23.2 mol H2O
you have to do stoichiometry - so start of with what you are given, which is 23.2 mols of hydrogen, then to cancel out mols of hydrogen, divide by what is in the equation: so 23.2 mols H2 / 2 mols H2. Next, to get mols of H2O multiply that number by the mols of water in the equation.
this answer makes sense because as you can see in the equation, there are 2 H2:2 H2O, so the amounts should be the same.
hope this helps! make sure to practice because it is ESSENTIAL that you understand this, especially if you plan on taking ap chem. good luck! :)
In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.
<h3>What is molarity?</h3>
Molarity (M) is a unit of concentration of solutions, and it is defined as the moles of a solute per liters of a solution.
- Step 1: Calculate the liters of solution required.
A chemist has a 3.00 M KBr solution and wants to measure 0.733 moles of KBr. The required volume is:
0.733 mol × (1 L/3.00 mol) = 0.244 L
- Step 2: Convert 0.244 L to mL.
We will use the conversion factor 1 L = 1000 mL.
0.244 L × (1000 mL/1 L) = 244 mL
In order to measure 0.733 moles of KBr from a 3.00 M solution, the chemist needs 244 mL of solution.
Learn more about molarity here: brainly.com/question/9118107