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antiseptic1488 [7]
3 years ago
8

At a horse show, there are both people and horses in the ring. Maria counted 22 heads and 64 legs. How many horses and people ar

e in the ring?
Mathematics
1 answer:
kondor19780726 [428]3 years ago
4 0
There are 14 horses and 8 men.
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<u>Answer:The chocolate are 0.0042 lighter than the stated on the label</u>

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Use the substitution method to solve the system of equations.
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Insert 3x - 7 for y in 15x - 5y = 14
15x - 5(3x - 7) = 14
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3 years ago
The annual water usage in rockport increases at a rate of 10% every year as the town gets bigger. this year, the town used 6,740
Finger [1]

Answer:

<h2>46•18</h2>

Step-by-step explanation:

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2 years ago
Simplify the rational expression. State any restrictions on the variable n^4-11n^2+30/ n^4-7n^2+10
djyliett [7]
To factor both numerator and denominator in this rational expression we are going to substitute n^{2} with x; so n^{2} =x and n ^{4} =  x^{2}. This way we can rewrite the expression as follows:
\frac{n^{4}-11n^{2} +30 }{n^{2}-7n^{2} +10 } =  \frac{ x^{2} -11x+30}{ x^{2} -7x+10}
Now we have two much easier to factor expressions of the form a x^{2} +bx+c. For the numerator we need to find two numbers whose product is c (30) and its sum b (-11); those numbers are -5 and -6. (-5)(-6)=30 and -5-6=-11.
Similarly, for the denominator those numbers are -2 and -5. (-2)(-5)=10 and -2-5=-7. Now we can factor both numerator and denominator:
\frac{ x^{2} -11x+30}{ x^{2} -7x+10} = \frac{(x-6)(x-5)}{(x-2)(x-5)}
Notice that we have (x-5) in both numerator and denominator, so we can cancel those out:
\frac{x-6}{x-2}
But remember than x= n^{2}, so lets replace that to get back to our original variable:
\frac{n^{2}-6 }{n^{2}-2 }
Last but not least, the denominator of rational expression can't be zero, so the only restriction in the variable is n^{2} -2 \neq 0
n^{2}  \neq 2
n \neq +or- \sqrt{2}
5 0
4 years ago
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Step-by-step explanation:

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