The first step is calculating the number of HCl moles. The molar mass of HCl is AH+ACl which is 1+35,5=36,5 g/mole. The formula for the pH is -lg[H+] where [H+] is the molar concentration of protons in the solution. To find the molar concentration we need to divide the number of moles by the volume(L).
We get the number of moles by dividing the mass given in the problem to the molar mass of the compound.1.825/36.5=0.05 moles of HCl so 0.05 moles of
H+.Molarity=n/V=0.05/0.25=0.2moles/liter.The pH is -lg0.2=2.321.
No - a precipitation will occur though. Potassium nitrate is soluble in water, so the potassium and nitrate ions will remain spectator ions and stay in solution. Lead (II) hydroxide is not soluble, and will precipitate out of solution to form a solid product.