The unknown of this problem is the experimental percent of water in the compound in order to remove the water of hydrogen, given the following:
Mass of crucible, cover and contents before heating 23.54 g
Mass of empty crucible and cover 18.82 g
Mass of crucible, cover, and contents after heating to constant mass 20.94 g
In order to get the answer, determine the following:
Mass of hydrated salt used = 23.54 g – 18.82 g = 4.72 g
Mass of dehydrated salt after heating = 20.94 g – 18.82 g = 2.12 g
Mass of water liberated from salt = 4.72 g – 2.12 g = 2.60 g
Then solve the percent of water in the hydrated salt by:
% water = (mass of water / mass of hydrated salt) x 100
% water = 2.60 g / 4.72 g x 100
% water = 55.08 % in the compound
Monitoring and regulating nuclear waste generated and issues associated to it the US.
Answer:
See Explanation
Explanation:
For SF6;
Since;
1.25 g of S corresponds to 4.44g of F
1 g of sulphur corresponds to 1 * 4.44/1.25 = 3.55
For SF4;
Since;
1.88 g of S corresponds to 4.44g of F
1 g of sulphur corresponds to 1 * 4.44/ 1.88 = 2.36
Hence;
Mass of oxygen per gram of sulphur in SF6/Mass of oxygen per gram of sulphur in SF4
=
3.55/2.36 = 1.5
Hence the law of multiple proportion is obeyed here.
Answer
Sounds travel slowest in gasses so it would be air
Explanation:
Mole ratio of Zn to HCl = 1 : 2.
If we use all 2.0mol of Zn, we would need 2.0 * 2 = 4.0mol of HCl. However we only have 3.0mol of HCl.
Therefore HCl is limiting.
