They are examples of elements because there's only one molecule in both
Answer:
<u>4</u>H₂O(l) →<u> 4</u>H₂(g) + <u>2</u>O₂(g)
Balancing equations
1. 3Fe(s) + 4H₂O(g) → Fe₃0₄(s) + 4H₂(g)
2. 2AlBr₃(aq) + 3Cl₂(g) → 2AlCl₃(aq) + 3Br₂(l)
3. 2HNO₃(aq) + Ba(OH)₂(aq) → Ba(NO₃)₂(aq) + 2H₂O(l)
4. 2Al(s) + 3Pb(NO₃)₂ → 2Al(NO₃)₃(aq) + 3Pb(s)
5. 3NaOH(aq) + Fe(NO₃)₃ → Fe(OH)₃(s) + 3NaNO₃(aq)
Explanation:
From the question given, I have been able to balance the chemical equations correctly.
In balancing chemical equations, the chemical equation must have equal number of atoms for each element that are both in the reactant side and in the product side.
For the above to be achieved, the number of atoms in each element will have to be multiplied and added.
A look at the balanced chemical equation above, you will discover that each element has the same number of atoms both in the reactant side and in the product side.
Preparation
• Grate a small red cabbage. If you do not want to grate the entire cabbage, grating half of a cabbage should be enough. Put the fine, pulpy grated cabbage into a large bowl or pot.
• Boil a pot of water. Use caution when handling the boiling water. Pour the boiling water into the bowl with the cabbage pulp until the water just covers the cabbage.
• Leave the cabbage mixture steeping, stirring occasionally, until the liquid is room temperature. This should take at least half an hour. The liquid will become red or purplish-red in color.
• Place a strainer over another large bowl or pot and pour the cabbage mixture through the strainer to remove the cabbage pulp. Press down on the pulp in the strainer, such as by using a large spoon, to squeeze more liquid out of the pulp.
• In the bowl, you should now have only liquid that will either be purple or blue in color. This will be your indicator solution, which you will use to test the pH of different liquids.
<span>• Children should wear goggles or other protective eyewear and adults should supervise and use caution when handling bleach and vinegar, because they can irritate eyes and skin.</span>
Answer:
The correct answer is 2.33g of 
, A
Explanation:
We can use basic stoich to get this question.
To start, lets convert our grams to moles in order to use our equation. 5.38g of 
moles.
We then can use our molar ratio of 13:10. Simply divide by our molar ratio in order to go from moles of 
to moles of . This gets us 0.129335 moles of .
Now lets convert to grams of by multiplying by the molar mass of . 
of
Answer:
<em>Neutron (¹₀n)</em>
Explanation:
<em>Nuclear Fission: </em>This is a process in which two or more light nuclei fuse or combine to form a heavier nucleus with a release of energy and radiation.
<em>Neutron: </em><em>A neutron is located in the nucleus of an atom, It has a neutral charge, The mass of neutron is 1.660540 x 10⁻²⁷ kg</em>
Therefore The type of radiation emitted during a nuclear process in which a nucleus with greater atomic number is formed is <em>Neutron (¹₀n)</em>
