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wolverine [178]
3 years ago
6

A force vector points due east and has a magnitude of 150 newtons. A second force is added to . The resultant of the two vectors

has a magnitude of 390 newtons and points along the (a) east/ (b) west line. Find the magnitude and direction of . Note that there are two answers.
Physics
1 answer:
balandron [24]3 years ago
6 0

Answer:

a. 240 N due east

b. 540 N due west

Explanation:

Let east be the reference direction

(a) if the resultant force has a magnitude of 390 N and points east, and the 1st force is 150N due East, then the additional force would also due east and has a magnitude of

390 - 150 = 240 N

(b) if the resultant force has a magnitude of 390 N and points west, it would be -390N is eastern reference, and the 1st force is 150N due East, then the additional force would also due east and has a magnitude of

-390 - 150 = -540 N

This force would point west

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Magnesium has atomic number 12, which means it has 12 protons and 12 electrons. It lost two electrons to form magnesium cation (Mg²⁺) with stable electron configuration like closest noble gas neon (Ne) with 10 electrons.

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Explanation:

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A train whose proper length is 1200 m passes at a high speed through a station whose platform measures 900 m, and the station ma
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0.66c

Explanation:

Use length contraction equation:

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900 = 1200 √(1 − (v²/c²))

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Which planets are visible without a telescope
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3 years ago
An elevator and its load have a combined mass of 1650 kg. Find the tension in the supporting cable when the elevator, originally
gizmo_the_mogwai [7]

Answer:

Tension in the supporting cable is = 4,866 N ≅4.9 KN

Explanation:

First of all, we need to understand that tension is a force, so the motion law

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From Newtons third law of motion, action and reaction are equal and opposite. This means that the force experienced by the elevator, is equal to the tension experienced by the spring.

Parameters given:

Mass of load = 1650 kg

Acceleration of load = ?

The acceleration of the load can be obtained by diving the change in velocity by the time taken. But we need to know the time taken for the motion to 41 m.

Time taken = distance covered / velocity

= \frac{41m}{11m/s} = 3.73 seconds

∴Acceleration = ( initial velocity - final velocity )/ time taken

Note: Final velocity is = 0 since the body came to a rest.

Acceleration = \frac{11 - 0 m/s}{3.73s} = 2.95m/s^{2}

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