Find the voltage change when: a. An electric field does 12 J of work on a 0.0001-C charge. b. The same electric field does 24 J
1 answer:
Explanation:
Given that,
(a) Work done by the electric field is 12 J on a 0.0001 C of charge. The electric potential is defined as the work done per unit charged particles. It is given by :
(b) Similarly, same electric field does 24 J of work on a 0.0002-C charge. The electric potential difference is given by :
Therefore, this is the required solution.
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Answer:
Imp = 25 [kg*m/s]
v₂= 20 [m/s]
Explanation:
In order to solve these problems, we must use the principle of conservation of linear momentum or momentum.
1)
where:
m₁ = mass of the object = 5 [kg]
v₁ = initial velocity = 0 (initially at rest)
F = force = 5 [N]
t = time = 5 [s]
v₂ = velocity after the momentum [m/s]
2)
Answer:
The angle between the blue beam and the red beam in the acrylic block is
Explanation:
From the question we are told that
The refractive index of the transparent acrylic plastic for blue light is
The wavelength of the blue light is
The refractive index of the transparent acrylic plastic for red light is
The wavelength of the red light is
The incidence angle is
Generally from Snell's law the angle of refraction of the blue light in the acrylic block is mathematically represented as
Where is the refractive index of air which have a value of
So
Generally from Snell's law the angle of refraction of the red light in the acrylic block is mathematically represented as
Where is the refractive index of air which have a value of
So
The angle between the blue beam and the red beam in the acrylic block
substituting values