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vova2212 [387]
3 years ago
5

A. Water has many unique properties. Identify a property of water and explain why this property makes water vital to living orga

nism.
b. Write one or two sentences that summarize Pascal's principle.

c. A force of 14,00 N is exerted on a piston that has an area of 0.020 m^2. What is the force exerted by a second piston that has an area of 0.040 m^2.

d. An object's weight is greater than its buoyant force in water. What would you expect to happen when the object is placed in water? Explain your answer.

e. A cannon is recovered from a shipwreck. Why does the buoyant force on the cannon stay the same as long as it is fully under water? Explain your reasoning.

f. An object sinks in both water and soil, so it displaces the same volume of each liquid. Oi is less dense than water. Why is the buoyant force acting on the object greater in water than it is in oil?

g. Use the flow rate equation to help explain how the motion of a whitewater raft changes as the river channel becomes narrower.
Physics
1 answer:
rosijanka [135]3 years ago
8 0

a) It can dissolve other substances and has high specific heat capacity.

b) Pressure is transferred equally in all directions

c) F=14*0.04/0.02=28 N

d) I'd expect that it will sink cause weight will pull it to the bottom

e) Because the buoyant force is stipulated by difference between pressures in the top and bottom surfaces of a body.

f) Because this force increases in denser liquids: F_b=\rho gV, where rho is density.

g) Q=Av, where v - speed, A - area. With the same flow rate v=Q/A, so larger area decreases speed and vice versa.

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How is pressure measured? question 1 options: pressure is measured as force per inch. pressure is measured as force per gram. pr
natita [175]

Pressure is measured as force per unit area, which is the third option.

<h3>What is pressure?</h3>

Pressure is amount of force that is applied over a given area divided by the size of this area.

Pressure is calculated by multiplying the force applied on the object by the area covered.

Since force is measured in Newtons (N) and area is measured in m², the unit of pressure is Nm².

Therefore, pressure is measured as force per unit area.

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brainly.com/question/12971272

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7 0
2 years ago
To which group/family does each of these belong? A. Sulfur _________ B. Sodium _________ C. Argon _________ D. Silicon _________
ArbitrLikvidat [17]

Answer:

A. Sulfur _________ group 16 chalcogens

B. Sodium _________ group 1 alkali metals

C. Argon _________ group 18 noble gases

D. Silicon _________ group 14 carbon family

E. Chlorine _________ group 17 halogens

F. Phosphorus_________ group 15 pnicogens

7 0
2 years ago
A .5 kg air puck moves to the right at 3 m/s, colliding with a 1.5kg air puck that is moving to the left at 1.5 m/s.
arlik [135]

Answer:

part (a) v = 1.7 m/s towards right direction

part (b) Not an elastic collision

part (c) F = -228.6 N towards left.

Explanation:

Given,

  • Mass of the first puck = m_1\ =\ 5\ kg
  • Mass of the second puck = m_2\ =\ 3\ kg
  • initial velocity of the first puck = u_1\ =\ 3\ m/s.
  • Initial velocity of the second puck = u_2\ =\ -1.5\ m/s.

Part (a)

Pucks are stick together after the collision, therefore the final velocities of the pucks are same as v.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ =\ (m_1\ +\ m_2)v\\\Rightarrow v\ =\ \dfrac{m_1u_1\ +\ m_2u_2}{m_1\ +\ m_2}\\\Rightarrow v\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5}{5\ +\ 1.5}\\\Rightarrow v\ =\ 1.7\ m/s.

Direction of the velocity is towards right due to positive velocity.

part (b)

Given,

Final velocity of the second puck = v_2\ =\ 2.31\ m/s.

Let v_1 be the final velocity of first puck after the collision.

From the conservation of linear momentum,

m_1u_1\ +\ m_2u_2\ +\ m_1v_1\ +\ m_2v_2\\\Rightarrow v_1\ =\ \dfrac{m_1u_1\ +\ m_2u_2\ -\ m_2v_2}{m_1}\\\Rightarrow v_1\ =\ \dfrac{5\times 3\ -\ 1.5\times 1.5\ -\ 1.5\times 2.31}{5}\\\Rightarrow v_1\ =\ 1.857\ m/s.

For elastic collision, the coefficient of restitution should be 1.

From the equation of the restitution,

v_1\ -\ v_2\ =\ e(u_2\ -\ u_1)\\\Rightarrow e\ =\ \dfrac{v_1\ -\ v_2}{u_2\ -\ u_1}\\\Rightarrow e\ =\ \dfrac{1.857\ -\ 2.31}{-1.5\ -\ 3}\\\Rightarrow e\ =\ 0.1\\

Therefore the collision is not elastic collision.

part (c)

Given,

Time of impact = t = 25\times 10^{-3}\ sec

we know that the impulse on an object due to a force is equal to the change in momentum of the object due to the collision,

\therefore I\ =\ \ m_1v_1\ -\ m_1u_1\\\Rightarrow F\times t\ =\ m_1(v_1\ -\ u_1)\\\Rightarrow F\ =\ \dfrac{m_1(v_1\ -\ u_1)}{t}\\\Rightarrow F\ =\ \dfrac{5\times (1.857\ -\ 3)}{25\times 10^{-3}}\\\Rightarrow F\ =\ -228.6\ N

Negative sign indicates that the force is towards in the left side of the movement of the first puck.

3 0
3 years ago
The search for black holes involves searching for The search for black holes involves searching for Group of answer choices sing
trasher [3.6K]

Answer:

Large spherical regions from which no light is detected

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A black hole is an object that has an extremely high density such that it possesses very powerful gravitational force that prevents the escape of all objects including light from it, and consumes nearby objects.

Due to the power of the gravitational force of a black hole, at the center, objects are infinitesimally compressed resulting in the inapplicability of the concept of space and time and the location is known as a singularity

Therefore, the search for black holes involves searching for <em>large spherical regions from which no light is detected</em>.

4 0
2 years ago
Uses of concave lens​
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Answer:

Concave Lens Uses. Telescope and Binoculars Spectacles Lasers Cameras FlashlightsPeepholes. ...

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Use of concave lens in cameras. ...

Used in flashlights. ...

Concave lens used in peepholes.

3 0
2 years ago
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