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Monica [59]
3 years ago
15

A net force of +15 N changes the momentum of an object by +100 kg-m/s. What is the time over which the force is applied? (please

explain!!)
A. 0.15 s
B. 6.7 s
C. 85 s
D. 150 s
Physics
1 answer:
sattari [20]3 years ago
3 0
As momentum / time = force
so; time = 100÷15

so your answer is 6.7 !!
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Which of the following are basic principles that apply to circuits? Choose the 2 correct answers from the choices below.
marta [7]

The basic principles that apply to circuits is that electrons must receive energy from a source, and electrons transfer energy to perform some useful function.

<h3 /><h3>What is circuit?</h3>

Individual electronic components, like resistors, transistors, are connected by metallic wires or traces by which the electric current can flow to form a circuit design.

The basic principles that apply to circuits will be;

1. Electrons must receive energy from a source.

2. Electrons transfer energy to perform some useful function.

Hence, option 1 and 2 are correct.

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5 0
2 years ago
A 1kw electric heater is switched on for ten minutes. how much heat does it produce​
Ainat [17]

H= P × t

1kW= 1000w

10 min = 600s

H= 1000×600=600,000J

=> 143.40kcal

4 0
3 years ago
What change occurs to the mass of an object when an unbalanced force is applied to it
strojnjashka [21]
The mass of an object always stays the same since it is really just the amount of matter in an object so no matter the force applied, as long as the object does not lose or gain matter, the object stays the same
5 0
2 years ago
An engine converts 95% of its energy to mechanical. What happens to the other 5% of its energy?
Elza [17]

Answer:

Here, 5% of energy wasted as a heat lost or work done against frictional forces.

Explanation:

No engine has yet made that can convert its all input energy into mechanical energy. Some of the input energy goes in vain in the form of heat and friction.

6 0
3 years ago
A department store sells an ""astronomical telescope"" with an objective lens of 30 cm focal length and an eyepiece lens of foca
Yuliya22 [10]

Answer:

The magnifying power of this telescope is (-60).

Explanation:

Given that,

The focal length of the objective lens of an astronomical telescope, f_o=30\ cm

The focal length of the eyepiece lens of an astronomical telescope, f_e=5\ mm=0.5\ cm

To find,

The magnifying power of this telescope.

Solution,

The ratio of focal length of the objective lens to the focal length of the eyepiece lens is called magnifying of the lens. It is given by :

m=\dfrac{-f_o}{f_e}

m=\dfrac{-30}{0.5}

m = -60

So, the magnifying power of this telescope is 60. Therefore, this is the required solution.

7 0
3 years ago
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