Answer:
The object displacement is 0 meters.
Explanation:
Because the expression for the object position as function of time is:
![x(t)= -4t + t^2](https://tex.z-dn.net/?f=%20x%28t%29%3D%20-4t%20%2B%20t%5E2)
At t= 3.0=t2 seconds the x-position of the object is:
![x(3.0)= -4(3.0) + (3.0)^2](https://tex.z-dn.net/?f=x%283.0%29%3D%20-4%283.0%29%20%2B%20%283.0%29%5E2%20)
![x(3.0s)=-3 m](https://tex.z-dn.net/?f=x%283.0s%29%3D-3%20m%20)
and at t=1.0=t1 seconds the x-position of the objects is:
![x(1.0)= -4(1.0) + (1.0)^2](https://tex.z-dn.net/?f=%20x%281.0%29%3D%20-4%281.0%29%20%2B%20%281.0%29%5E2)
![x(1.0s)=-3m](https://tex.z-dn.net/?f=x%281.0s%29%3D-3m%20)
The total displacement (
) of the object between t2 and t1 is the difference between x(3.0s) and x(1.0s):
![\Delta x= x(3.0)-x(1.0)=-3.0-(-3.0)](https://tex.z-dn.net/?f=%5CDelta%20x%3D%20x%283.0%29-x%281.0%29%3D-3.0-%28-3.0%29%20)
![\Delta x=0m](https://tex.z-dn.net/?f=%5CDelta%20x%3D0m%20)
The displacement of the object is zero!!!
The overall efficiency of this plant will be 83%. The plant's efficiency is calculated by dividing work output to that of heat supplied.
<h3>What is efficiency of the plant?</h3>
The efficiency of the plant is found as the ratio of work output to the heat supplied.
The heat supplied is found as;
Q= m h
Q=30,000 kJ/kg,× 60 tons/h
Q=30,000 ×10³×60×10³/3600
Q=3×10⁷×16.66
Q=180.720×10⁶
Q=180 mw
The overall efficiency of this plant is ;
![\eta = \frac{W}{Q_{supplied}} \\\\ \eta = \frac{150}{{180}} \\\\ \eta=0.833 \\\\ \eta= 83 \%](https://tex.z-dn.net/?f=%5Ceta%20%3D%20%5Cfrac%7BW%7D%7BQ_%7Bsupplied%7D%7D%20%5C%5C%5C%5C%20%5Ceta%20%3D%20%5Cfrac%7B150%7D%7B%7B180%7D%7D%20%5C%5C%5C%5C%20%5Ceta%3D0.833%20%5C%5C%5C%5C%20%5Ceta%3D%2083%20%5C%25)
The overall efficiency of this plant will be 83%.
To learn more about efficiency, refer:
brainly.com/question/13828557
#SPJ4
Answer:
I = 0.058 [A]
Explanation:
Ohm's law is defined as voltage equal to the product of current by resistance.
![V =I*R](https://tex.z-dn.net/?f=V%20%3DI%2AR)
where:
V = voltage = 4.2 [V]
I = current [amp]
R = resistivity = 72 [ohm]
Now clearing I, we have:
![I = V/R\\I = 4.2/72\\I = 0.058 [A]](https://tex.z-dn.net/?f=I%20%3D%20V%2FR%5C%5CI%20%3D%204.2%2F72%5C%5CI%20%3D%200.058%20%5BA%5D)
Answer:
C
Explanation:
That is where the most heat and light is showing on this diagram.
Answer:
The correct answer is:
(a) ![3.31\times 10^{10} \ \omega/m^2](https://tex.z-dn.net/?f=3.31%5Ctimes%2010%5E%7B10%7D%20%5C%20%5Comega%2Fm%5E2)
(b) ![5\times 10^6 \ N/C](https://tex.z-dn.net/?f=5%5Ctimes%2010%5E6%20%5C%20N%2FC)
Explanation:
The given values are:
Power of Laser beam,
= 10 mW
on converting it, we get
= ![10\times 10^{-3} \ \omega](https://tex.z-dn.net/?f=10%5Ctimes%2010%5E%7B-3%7D%20%5C%20%5Comega)
= ![10^{-2} \ \omega](https://tex.z-dn.net/?f=10%5E%7B-2%7D%20%5C%20%5Comega)
Spot's diameter,
= 0.62 μm
= ![0.62\times 10^{-6} \ m](https://tex.z-dn.net/?f=0.62%5Ctimes%2010%5E%7B-6%7D%20%5C%20m)
Now,
(a)
The intensity of light will be:
⇒ ![I=\frac{P}{\pi r^2}](https://tex.z-dn.net/?f=I%3D%5Cfrac%7BP%7D%7B%5Cpi%20%20r%5E2%7D)
or,
⇒ ![=\frac{4P}{\pi d^2}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B4P%7D%7B%5Cpi%20d%5E2%7D)
On substituting the values, we get
⇒ ![=\frac{4\times 10^{-2}}{\pi(0.62)^2\times 10^{-12}}](https://tex.z-dn.net/?f=%3D%5Cfrac%7B4%5Ctimes%2010%5E%7B-2%7D%7D%7B%5Cpi%280.62%29%5E2%5Ctimes%2010%5E%7B-12%7D%7D)
⇒ ![=3.31\times 10^{10} \ \omega/m^2](https://tex.z-dn.net/?f=%3D3.31%5Ctimes%2010%5E%7B10%7D%20%5C%20%5Comega%2Fm%5E2)
(b)
The amplitude of electric field will be:
⇒ ![I=\frac{1}{2}\epsilon_0E_0.C](https://tex.z-dn.net/?f=I%3D%5Cfrac%7B1%7D%7B2%7D%5Cepsilon_0E_0.C)
or,
⇒ ![E_0=\sqrt{\frac{2I}{CE_0} }](https://tex.z-dn.net/?f=E_0%3D%5Csqrt%7B%5Cfrac%7B2I%7D%7BCE_0%7D%20%7D)
On substituting the values, we get
⇒ ![=\sqrt{\frac{3.31\times 10^{10}\times 2}{3\times 10^8\times 8.85\times 10^{-12}} }](https://tex.z-dn.net/?f=%3D%5Csqrt%7B%5Cfrac%7B3.31%5Ctimes%2010%5E%7B10%7D%5Ctimes%202%7D%7B3%5Ctimes%2010%5E8%5Ctimes%208.85%5Ctimes%2010%5E%7B-12%7D%7D%20%7D)
⇒ ![=5\times 10^6 \ V/m](https://tex.z-dn.net/?f=%3D5%5Ctimes%2010%5E6%20%5C%20V%2Fm)