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Flura [38]
3 years ago
8

The length of second, s pendulum at a place where gravitational acceleration ]g] is 9.8 m/s

Physics
1 answer:
amm18123 years ago
6 0
O.99 m long .simple pendulum time period is 2s for second formula then use formula T=2pi.rt(lenght/gravity)
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What would be the projectile's initial speed?
zalisa [80]

Math is the process of using the given information, along with
all the general stuff that you know, to find the missing information. 
With no given information, we have no way to even guess at
an answer.

8 0
3 years ago
Assume it takes 10 J to stretch a spring 10 cm beyond its natural length. Find the work required (in Joules) to stretch the spri
Lady bird [3.3K]

Answer:

W = 30 J

Explanation:

given,

Work done = 10 J

Stretch of spring, x = 0.1 m

We know,

dW = F .dx

we know, F = k x

\int dW = \int_0^{0.1} k.x dx

W = \int_0^{0.1} k.x dx

W = k[\dfrac{x^2}{2}]_0^{0.1}

10 = k\dfrac{0.1^2}{2}

k = 2000

now, calculating Work done by the spring when it stretched to 0.2 m from 0.1 m.

W = \int_{0.1}^{0.2} 2000 x dx

W = 2000 [\dfrac{x^2}{2}]_{0.1}^{0.2} dx

W = 1000 x 0.03

W = 30 J

Hence, work done is equal to 30 J.

4 0
3 years ago
PLS ANSWER ASAP
vivado [14]

Answer:

Cart A

Explanation:

Momentum can be computed by finding the product of mass and velocity. To solve this, you can use the formula below to find the greatest momentum:

p = mv

where:

p = momentum (kgm/s)       m = mass (kg)         v = velocity (m/s)

Because carts are moving along with the weights, we need to consider the whole system. This means that you need to add in the masses and the mass of the cart.

<u>Cart A:</u>

m = 200kg + 0 kg = 200 kg

v = 4.8 m/s

p = 200kg x 4.8 m/s = 960 kg-m/s

<u>Cart B:</u>

m = 200kg + 20 kg = 220 kg

v = 4.0 m/s

p = 220kg x 4.0 m/s = 880 kg-m/s

<u>Cart C:</u>

m = 200kg + 40 kg = 240 kg

v = 3.8 m/s

p = 240kg x 3.8 m/s = 912 kg-m/s

<u>Cart D:</u>

m = 200kg + 60 kg = 260 kg

v = 3.5 m/s

p = 260kg x 3.5 m/s = 910 kg-m/s

As you can see, Cart A has the greatest momentum.

5 0
3 years ago
Read 2 more answers
Please help me
Setler79 [48]

Answer:

This motion is known as Brownian motion.

Explanation:

This motion is known as Brownian motion.

5 0
3 years ago
A force of 10 newtons acts in a direction 75° above horizontal, moving an object 15 meters from (0, 0) to (15, 0). what is the w
hammer [34]

Work done by the force is 150 Joules.

Steps involved in the question:

Step one:

Given data

Force F= 10N

the distance is described by the coordinate =  (0,0) to (15,0)

hence the distance = 15m in the x-direction.

Step two:

Required is the work done

we know that work done is expressed as

Wd= Force* Distance

Wd= 10*15

Wd= 150 Joules

To learn more about work done refer : brainly.com/question/25573309

#SPJ4



6 0
2 years ago
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