Answer:
1. 53.415 m
2. 32.373 m/s
3. 30.82 m/s
Explanation:
Let g = 9.81 m/s2. We can use the following equation of motion to calculate the distance traveled by the ball in 3.3s, and the velocity it achieved
1.
2.
3. If the ball is kicked at 0.5 m above the ground then the net distance between the ball and the roof top is
53.415 - 0.5 = 48.415 m
For the ball to at least make it to the roof top at speed v = 0 m/s. We can use the following equation of motion to calculate the minimum initial speed
where v = 0 m/s is the final velocity of the ball when it reaches the rooftop, is the initial velocity,
is the distance traveled, g = -9.81 is the gravitational acceleration with direction opposite with velocity
Answer:
= 3.36 mm
Explanation:
From Ohm's law,
(Voltage = Current * Resistance)
The geometric definition of resistance is
where is the resistivity of the material,
and
are the length and cross-sectional area, respectively.
Since the wire is assumed to have a circular cross-section, its area is given by
where
is the diameter.
Resistivity of copper = . With these and other given values,
Answer:
Explanation:
From the question we are told that
Nucleus diameter
a 12C nucleus
Required kinetic energy
Generally initial speed of proton must be determined,applying the law of conservation of energy we have
where
=initial kinetic energy
=final kinetic energy
=initial electric potential
=final electric potential
mathematically
where
=distance b/w charges
=nucleus charge
=constant
=proton charge
Generally kinetic energy is know as
Therefore
Generally equation for radius is
Mathematically solving for radius of nucleus
Generally we can easily solving mathematically substitute into v_1
Therefore the proton must be fired out with a speed of
Answer:
a)
b)
Step-by-step explanation.
In order to solve this problem, we mus start by plotting the given points and charges. That will help us visualize the problem better and determine the direction of the forces (see attached picture).
Once we drew the points, we can start calculating the forces:
which yields:
(I will assume the positions are in meters)
Next, we can make use of the force formula:
so we substitute the values:
which yields:
Now we can find its components:
And we can now write them together for the first force, so we get:
We continue with the next force. The procedure is the same so we get:
which yields:
Next, we can make use of the force formula:
which yields:
Now we can find its components:
And we can now write them together for the second, so we get:
We continue with the next force. The procedure is the same so we get:
which yields:
Next, we can make use of the force formula:
which yields:
Now we can find its components:
And we can now write them together for the third force, so we get:
So in order to find the resultant force, we need to add the forces together:
so we get:
So when adding the problem together we get that:
which is the answer to part a), now let's take a look at part b).
b)
Basically, we need to find the magnitude of the force and divide it into the test charge, so we get:
which yields:
and now we take the formula for the electric field which is:
so we go ahead and substitute:
