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hodyreva [135]
3 years ago
11

What provides most of the force to allow the runners to move?

Physics
1 answer:
kobusy [5.1K]3 years ago
4 0

Answer:

When you are running the most important force that you should understand is friction. Friction is a force that opposes movement between two objects, but for runners friction makes you faster. Friction gives you a better and more efficient way to use your energy into speed.

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What can you say about the speed of light in diamond?
Inessa05 [86]
So n=c/v, n= index, c=speed of light and v= speed of light in diamond. 2.42=c/v so v=c/2.42, c≈<span>3x108 m/sec</span><span> so v=</span><span>1.24x108 m/sec</span>.
<span>Hope this helps.</span>
7 0
3 years ago
What do the mean by cubic expansivity​
olganol [36]
A real cubic expansivity is an increase in the volume of a liquid per unit volume per degree rise in temperature when heated in an inexpansible vessel.
5 0
2 years ago
Read 2 more answers
If a bullet travels at 593.0 m/s, what is its speed in miles per hour?
Ksenya-84 [330]

We have 1 \; mile = 1609.34\; meters. So, 1 \; meter = \frac{1}{1609.34} \;mile.

1 \; hour = 3600 \; s. So 1 \; s = \frac{1}{3600}  \; hour.

Thus we can convert the units of the given quantity.

That is,

593\;m/s=593\;\frac{1/1609.34}{1/3600} \;miles/hour\\&#10;593\;m/s=1,326.51\;miles/hour.

The quantity is converted to the required units.


7 0
3 years ago
The process that enhances some properties of an object at the expense of other properties is called:
lidiya [134]

Answer:

The answer is: letter a, pop-out effect.

Explanation:

The "pop-out effect" is a phenomenon which allows the person's precognitive processes to detect a<em> visual stimulus that is potentially the most meaningful one</em> in a person's spatial field of attention. The pop-up effect occurs when a person distinguishes one object from the rest.

For example, when a child chooses among pictures in different colors, it is common for the child to point at colored pictures rather than grayscale pictures. This is an example of a pop-out effect. <u>The properties of the colored pictures is more preferred by the child thus, causing him not to choose or mind the grayscale images.</u>

Thus, this explains the answer.

6 0
3 years ago
A 910-kg object is released from rest at an altitude of 1200 km above the north pole of the Earth. If we ignore atmospheric fric
gayaneshka [121]

In order to develop this problem it is necessary to use the concepts related to the conservation of both potential cinematic as gravitational energy,

KE = \fract{1}{2}mv^2

PE = GMm(\frac{1}{r_1}-(\frac{1}{r_2}))

Where,

M = Mass of Earth

m = Mass of Object

v = Velocity

r = Radius

G = Gravitational universal constant

Our values are given as,

m = 910 Kg

r_1 = 1200 + 6371 km = 7571km

r_2 = 6371 km,

Replacing we have,

\frac{1}{2} mv^2 =  -GMm(\frac{1}{r_1}-\frac{1}{r_2})

v^2 =  -2GM(\frac{1}{r_1}-\frac{1}{r_2})

v^2 = -2*(6.673 *10^-11)(5.98 *10^24) (\frac{1}{(7.571 *10^6)} -\frac{1}{(6.371 *10^6)})

v = 4456 m/s

Therefore the speed of the object when striking the surface of earth is 4456 m/s

3 0
4 years ago
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