Answer:
2.7 J
Explanation:
The energy of one photon is given by

where
h is the Planck constant
f is the frequency
For the photons in this problem,

So the energy of one photon is

The number of photons contained in 1.0 mol is
(Avogadro number)
So the total energy of
photons contained in 1.0 mol is

Answer:
Because Electrical Current is the most important thing about psychics
Explanation:
;p

According to above question ~
Let's find the charge (q) by using formula ~
Hence, 12 coulombs of charge flow past any point in the wire in 3 seconds
75 percent (calculated percentage %) of what number equals 27? Answer: 36.