The ml of 12.0 M HCL needed to prepare 905.0 ml of 1.00m hcl is calculated using M1V1 =M2V2 formula
M1= 12.0 M
V1=?
M2= 905.0 ml
V2 = 1.00M
V1 is therefore = M2V2/M1
=905 x 1.00/12.0 = 75.42 ml
Answer:
35.7%
Explanation:
The percent yield is calculated by the formula:
<em>[(actual yield) / (theoretical yield)] * 100</em>
In this case, the actual yield is 0.15 grams, and the theoretical yield is 0.42 grams. So, putting these values into the equation, we have:
Thus, the percent yield of 
is 35.7%.
Hope this helps!
Answer:
93.28%
Explanation:
To solve the percent yield we need to find theoretical yield:
<em>Percent yield = Actual Yield (452.78g) / Theoretical yield * 100</em>
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Theoretical yield is obtained converting the mass of acetylene to moles and using the balanced equation determine the moles of CO₂ produced assuming a 100% of reaction:
<em>Moles acetylene (Molar mass: 26.04g/mol)</em>
143.6g C₂H₂ * (1mol / 26.04g) = 5.515 moles C₂H₂
<em>Moles CO₂:</em>
5.515 moles C₂H₂ * (4 moles CO₂ / 2mol C₂H₂) = 11.029moles CO₂
<em>Mass CO₂ (Molar mass: 44.01g/mol):</em>
11.029moles CO₂ * (44.01g / mol) = 485.39g CO₂ is theoretical yield
Percent yield is:
Percent yield = 452.78g / 485.39g * 100
= 93.28%
<span>When naming acids, the prefix hydro- is used when the name of the acid anion ends in "-ide". Simple acids, known as binary acids, have only one anion and one hydrogen. These anions usually have the ending -ide. For example, hydrogen chloride becomes hydrochloric acid.</span>
