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VARVARA [1.3K]
3 years ago
8

Calculate the amount of energy required to increase the temperature of 18.0 go vapor water from 275.0 degrees * C to 385 degrees

* C (Specific heat of water)
Chemistry
1 answer:
Archy [21]3 years ago
8 0

Answer:

<u>The amount of energy required to increase temperature 275°C to 385°C is ΔQ =3.95208kJ</u>

Explanation:

Given :

  • <em>The mass of the water vapour is 18 g</em>
  • <em>The initial temperature : 275°C</em>
  • <em>The final temperature : 385°C</em>

According to the formula :

ΔQ = m*s*ΔT

Where ,

  • <em>ΔQ is the heat supplied</em>
  • <em>m is the mass of the substance (water vapour) = 18g</em>
  • <em>s is the specific heat of the substance ( water vapour) = 1.996Jg^{-1}K^{-1}</em>
  • <em>ΔT is the change in temperature =385-275=110K</em>

∴

ΔQ = 18*1.996*110\\=3952.08J

⇒ΔQ =3.95208kJ

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