Question

Calculate the amount of energy required to increase the temperature of 18.0 go vapor water from 275.0 degrees * C to 385 degrees * C (Specific heat of water)

Answer 1

Answer:

The amount of energy required to increase temperature 275°C to 385°C is ΔQ =3.95208kJ

Explanation:

Given :

• The mass of the water vapour is 18 g
• The initial temperature : 275°C
• The final temperature : 385°C

According to the formula :

Δ$Q = m*s*$Δ$T$

Where ,

• Δ$Q$ is the heat supplied
• $m$ is the mass of the substance (water vapour) = 18g
• $s$ is the specific heat of the substance ( water vapour) = $1.996Jg^{-1}K^{-1}$
• Δ$T$ is the change in temperature =$385-275=110K$

∴

ΔQ = $18*1.996*110\\=3952.08J$

⇒ΔQ =3.95208kJ