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3 years ago

6

______ is/are usually the best conductor/s. a. Metals c. Air b. Water d. Minerals Please select the best answer from the choices

provided A B C D

2 answers:

nataly862011 [7]3 years ago

8 0

Metals are the best conductors.

icang [17]3 years ago

5 0

The best conductors are either b or a sorry i can't help more

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State examples of a transverse wave.

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ripples on the surface of water.

vibrations in a guitar string.

a Mexican wave in a sports stadium.

electromagnetic waves – eg light waves, microwaves, radio waves.

seismic S-waves.

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3 years ago

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Definition of distance travelled?

Mekhanik [1.2K]

Answer:

distance traveled is a total length of the path traveled between two positions.

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Anika asks Eva to roll a basketball and then a bowling

Alex73 [517]

Answer:

the bowling ball, because it has more mass and therefore more inertia

Explanation:

As per law of inertia we know that if an object is having more inertia then it is difficult to change state of motion.

Inertia is the property of mass of an object which always resist to change the state of motion of the object.

If an object has more inertia then it is more difficult to change the state of motion.

Now we know that we have one bowling ball and one basket ball, since bowling ball is having more mass then it must have more inertia so it is difficult to start the motion in bowling ball.

So correct answer will be

the bowling ball, because it has more mass and therefore more inertia

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3 years ago

A rocket in deep space has an empty mass of 150 kg and exhausts the hot gases of burned fuel at 2500 m/s. It is loaded with 600

3241004551 [841]

Answer:

$v(10\,s) \approx 775.387\,\frac{m}{s}$

$v(20\,s)\approx 1905.350\,\frac{m}{s}$

$v(30\,s) \approx 4023.595\,\frac{m}{s}$

Explanation:

The speed of the rocket is given the Tsiolkovsky's differential equation, whose solution is:

$v (t) = v_{o} - v_{ex}\cdot \ln \frac{m}{m_{o}}$

Where:

$v_{o}$ - Initial speed of the rocket, in m/s.

$v_{ex}$ - Exhaust gas speed, in m/s.

$m_{o}$ - Initial total mass of the rocket, in kg.

$m$ - Current total mass of the rocket, in kg.

Let assume that fuel is burned linearly. So that,

$m(t) = m_{o} + r\cdot t$

The initial total mass of the rocket is:

$m_{o} = 750\,kg$

The fuel consumption rate is:

$r = -\frac{600\,kg}{30\,s}$

$r = -20\,\frac{kg}{s}$

The function for the current total mass of the rocket is:

$m(t) = 750\,kg - (20\,\frac{kg}{s} )\cdot t$

The speed function of the rocket is:

$v(t) = - 2500\,\frac{m}{s}\cdot \ln \frac{750\,kg -(20\,\frac{kg}{s} )\cdot t}{750\,kg}$

The speed of the rocket at given instants are:

$v(10\,s) \approx 775.387\,\frac{m}{s}$

$v(20\,s)\approx 1905.350\,\frac{m}{s}$

$v(30\,s) \approx 4023.595\,\frac{m}{s}$

7 0

3 years ago

Planets A and B have the same size, mass, and direction of travel, but planet

Luden [163]

Answer:

A. You would weigh the same on both planets because their masses and the distance to their centers of gravity are the same.

Explanation:

Given that Planets A and B have the same size, mass.

Let the masses of the planets A and B are and respectively.

As masses are equal, so .

Similarly, let the radii of the planets A and B are and respectively.

As radii are equal, so .

Let my mass is m.

As the weight of any object on the planet is equal to the gravitational force exerted by the planet on the object.

So, my weight on planet A,

my weight of planet B,

By using equations (i) and (ii),

.

So, the weight on both planets is the same because their masses and the distance to their centers of gravity are the same.

Hence, option (A) is correct.

7 0

2 years ago