Three units deformations observed in these bands.
<h3>What forces do a rubber band encounter?</h3>
Elastic force is the force that permits some materials to regain their former shape after being stretched or crushed. Thus, a stretched rubber band is subject to an elastic force.
The rubber band experiment uses a straightforward rubber band to show entropic force and a refrigeration cycle. The rubber band experiment involves stretching and then releasing a rubber band while measuring its temperature.
Always acting in the opposite direction of motion is friction. This indicates that if friction is there, it cancels out some of the force driving the motion (if the object is being accelerated). This results in a decreased acceleration and a smaller net force.
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Thick lens will have shorter and consequently thin lens will have greater focal length. Because, For a thick lens, the optical path length of the light is more, than for a thin lens, thus, the bending of light will be more in case of a thicker lens. Consequently, it has a shorter focal length.
Answer:
When a positive charged object is placed near a conductor electrons are attracted the the object. ... When electric voltage is applied, an electric field within the metal triggers the movement of the electrons, making them shift from one end to another end of the conductor. Electrons will move toward the positive side. As you know, electrons are always moving. They spin very quickly around the nucleus of an atom. As the electrons zip around, they can move in any direction, as long as they stay in their shell.
Answer:
Vf = final velocity = 1.96 [m/s]
Explanation:
To solve this problem we must use the following equation of kinematics.
where:
Vf = final velocity [m/s]
Vo = initial velocity = 9.98 [m/s]
g = gravity acceleration = 9.81 [m/s²]
x = vertical distance [m]
![v_{f}^{2}=(9.98)^{2}-2*9.81*4.88\\v_{f}^{2} = 99.6-95.74\\v_{f}=\sqrt{3.8544}\\v_{f}=1.96[m/s]](https://tex.z-dn.net/?f=v_%7Bf%7D%5E%7B2%7D%3D%289.98%29%5E%7B2%7D-2%2A9.81%2A4.88%5C%5Cv_%7Bf%7D%5E%7B2%7D%20%3D%2099.6-95.74%5C%5Cv_%7Bf%7D%3D%5Csqrt%7B3.8544%7D%5C%5Cv_%7Bf%7D%3D1.96%5Bm%2Fs%5D)
Note: The negative sign of the gravity acceleration means that the gravity acceleration is pointing in the opposite direction of the movement.
