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Mashutka [201]
3 years ago
9

In a binary star system, an unseen component is found to have 8 solar masses. It would be visible if the system were a normal st

ar, so it must be a collapsed object. Theoretical considerations tell us that it must be a:__________
Physics
1 answer:
maksim [4K]3 years ago
5 0

Answer:

Black Hole

Explanation:

A black hole is a very dense and massive stellar object, which has a field of gravity so large that not even light can escape it.

Since it does not emit light, <u>we cannot see them directly</u>, hence the name of black hole.

So in this case,<u> if the object has a mass of 8 solar masses that is enough to form a black hole</u>, and <u>also cannot be seen</u>, all of this indicates that the object we are talking about is a black hole.

It should be mentioned that although these objects do not emit light, because it cannot escape due to the immense force of gravity, black holes can be detected by a type of radiation emitted on their event horizon due to quantum effects called Hawking radiation .

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A motorcyclist travels around a curved path that has a radius of 350 ft. While traveling around the curved path, the motorcyclis
Ilya [14]

Answer:

A) t = 29.3 s

B) V = 58.56 ft/s

C) a_net = 2.3 ft/s²

Explanation:

A) The formula for radial acceleration is given as;

a_c = V²/R

We are given;

Radius;R = 350 ft

So, a_c = V²/350

Where V is velocity

Tangential acceleration;a_t = 2 ft/s²

Formula for net acceleration is;

a_net = √((a_c)² + (a_t)²)

We are given a_net = 10 ft/s²

Thus;

10 = √(V²/350)² + (2²)

10² = V⁴/350² + 4

100 - 4 = V⁴/350²

96 × 350² = V⁴

V = 58.56 ft/s

Now, formula for angular velocity is;

ω = V/r

ω = 58.56/350

ω = 0.1673 rad/s

Angular acceleration is given by;

α = a_t/r

α = 2/350

α = 0.00571 rad/s²

Time needed will be gotten from the formula;

t = ω/α

t = 0.1673/0.00571

t = 29.3 s

B) we are told total acceleration is 10 ft/s², thus it's the same as velocity gotten earlier which is 58.56 ft/s

C) we are told that the speed is now 20 ft/s

Thus;

a_c = 20²/350

a_c = 1.1429 ft/s²

Since a_net = √((a_c)² + (a_t)²)

We are given a_t = 2 ft/s²

Thua;

a_net = √(1.1429² + 2²)

a_net = √5.30622041

a_net = 2.3 ft/s²

6 0
3 years ago
Suppose you have a pendulum clock that keeps correct time on Earth (acceleration due to
vekshin1

Answer:

dont know because I am a student lol

8 0
3 years ago
Read 2 more answers
When a potential V is applied across a capacitor, a charge q is stored. What charge is stored if the potential across the capaci
Readme [11.4K]

Answer:

q' = 0.5q

Hence, the charge stored is also halved

Explanation:

The capacitance of a capacitor is given by the following formula:

C = \frac{q}{V} ------- eqn(1)

where,

C = Capacitance of the capacitor

q = charge stored in the capacitor

V = potential across the capacitor

Now, if we make potential half of its initial value:

C = \frac{q'}{0.5V}\\\\CV = 2q'\\using\ eqn(1):\\\frac{q}{V}(V) = 2q'\\\\<u></u>

<u>q' = 0.5q </u>

<u>Hence, the charge stored is also halved </u>

4 0
3 years ago
A car with mass 1600 kg drives around a flat circular track of radius 28.0 m. The coefficient of friction between the car tires
egoroff_w [7]

Answer:

v=15.24 m/s

Explanation:

Given that

Mass ,m= 1600 kg

radius ,r= 28 m

Coefficient of friction ,μ = 0.83

The radial force on the car when it takes turn

F=\dfrac{mv^2}{r}

The friction force on the car

Fr= μ m g

The condition for motion without losing traction

F= Fr

\dfrac{mv^2}{r}=\mu\ m g

v²=μ r g

v=\sqrt{\mu\ r g}

Now by putting the values

v=\sqrt{0.83\times 28\times 10}\ m/s  ( take g=10m/s²)

v=15.24 m/s

The speed of the car will be 15.24 m/s

5 0
3 years ago
Study the image of the moving car.
lora16 [44]

Answer:

Low Potential energy and High Kinetic energy

Explanation:

Hope this helps and have a good day! Apologies if it's wrong.<3

3 0
2 years ago
Read 2 more answers
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