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2 years ago

Which are precautions to take when working with heat and fire?

Physics

1 answer:

shtirl [24]2 years ago

3 0

Always wear protected face gear and body gear, make sure you have an adult present and a fire extinguisher

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Explain why gases are more compressible than solid

Oduvanchick [21]

Answer:

If we put pressure on a solid or a liquid, there is essentially no change in volume. ... The kinetic-molecular theory explains why gases are more compressible than either liquids or solids. Gases are compressible because most of the volume of a gas is composed of the large amounts of empty space between the gas particles.

Explanation:

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2 years ago

A boy wants use his slingshot to shoot a water balloon into the air. His

Marrrta [24]

Answer:

A. 70 m OS the correct one

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3 years ago

What is measurements?

Sliva [168]

Answer:

the action of measuring something.

Measurement is a comparison of an unknown quantity with a known fixed quantity of the same kind. The value obtained on measuring a quantity is called its magnitude. Magnitude of a quantity is expressed as numbers in its units.

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3 years ago

Read 2 more answers

the value of acceleration due to gravity option A is same on equator and poles option B is list on poles option C is list on equ

stiks02 [169]

Answer:

D. Increases from pole to equator

Explanation:

I majored in Science

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2 years ago

A helium nucleus (charge = 2e, mass = 6.63 10-27 kg) traveling at 6.20 105 m/s enters an electric field, traveling from point ci

MA_775_DIABLO [31]

Answer:

$v_B=3.78\times 10^5\ m/s$

Explanation:

It is given that,

Charge on helium nucleus is 2e and its mass is $6.63\times 10^{-27}\ kg$

Speed of nucleus at A is $v_A=6.2\times 10^5\ m/s$

Potential at point A, $V_A=1.5\times 10^3\ V$

Potential at point B, $V_B=4\times 10^3\ V$

We need to find the speed at point B on the circle. It is based on the concept of conservation of energy such that :

increase in kinetic energy = increase in potential×charge

$\dfrac{1}{2}m(v_A^2-v_B^2)=(V_B-V_A)q\\\\\dfrac{1}{2}m(v_A^2-v_B^2)={(4\times 10^3-1.5\times 10^3)}\times 2\times 1.6\times 10^{-19}=8\times 10^{-16}\\\\v_A^2-v_B^2=\dfrac{2\times 8\times 10^{-16}}{6.63\times 10^{-27}}\\\\v_A^2-v_B^2=2.41\times 10^{11}\\\\v_B^2=(6.2\times 10^5)^2-2.41\times 10^{11}\\\\v_B=3.78\times 10^5\ m/s$

So, the speed at point B is $3.78\times 10^5\ m/s$ .

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3 years ago