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djverab [1.8K]
3 years ago
13

Which are precautions to take when working with heat and fire?

Physics
1 answer:
shtirl [24]3 years ago
3 0
Always wear protected face gear and body gear, make sure you have an adult present and a fire extinguisher
You might be interested in
Calculate the speed of a car if it covers the distance of 100m in 5seconds​.
NeTakaya

Answer:

200m/s

Explanation:

v =  \frac{displacement}{time}

8 0
2 years ago
Read 2 more answers
Tarzan swings on a 35.0 m long vine initially inclined at an angle of 44.0◦ with the vertical. The acceleration of gravity if 9.
maks197457 [2]

Answer:

(A) Vf = 13.8 m/s

(B)  Vf = 15.1 m/s      

Explanation:

length of rope (L) = 35 m

angle to the vertical = 44 degrees

acceleration due to gravity (g) = 9.8 m/s^{2}

(A) from conservation of energy

final kinetic energy + final potential energy = initial kinetic energy + initial potential energy

0.5m(Vf)^{2} + mg(Hf) =  0.5m(Vi)^{2} + mg(Hi)

where

m = mass

Hi = initial height = 35 cos 44 = 25.17

Hf = final height = length of vine = 35 m

Vi = initial velocity = 0 since he starts from rest

Vf = final velocity

the equation now becomes

0.5m(Vf)^{2} + mg(Hf) = mg(Hi)

0.5m(Vf)^{2} = mg (Hi - Hf)

0.5(Vf)^{2} = g (Hi - Hf)

0.5(Vf)^{2} = 9.8 x (25.17 - 35)

0.5(Vf)^{2} = - 96.3  (the negative sign tells us the direction of motion is downwards)

Vf = 13.8 m/s

(B) when the initial velocity is 6 m/s the equation remains

      0.5m(Vf)^{2} + mg(Hf) =  0.5m(Vi)^{2} + mg(Hi)

       m(0.5(Vf)^{2} + g(Hf)) =  m(0.5(Vi)^{2} + g(Hi))

      0.5(Vf)^{2} + g(Hf) = 0.5(Vi)^{2} + g(Hi)

      0.5(Vf)^{2} = 0.5(Vi)^{2} + g(Hi) - g(Hf)

       0.5(Vf)^{2} = 0.5(6)^{2} + (9.8 x (25.17 - 35))

        0.5(Vf)^{2} =  -114.3  ( just as above, the negative sign tells us the direction of motion is downwards)      

       Vf = 15.1 m/s

5 0
3 years ago
Read 2 more answers
The velocity of 200kg object changes from 10m/s to 22m/s in 12 sec.what is the force on the accelerated object?
Vikentia [17]
  • Initial velocity (u) = 10 m/s
  • Final velocity (v) = 22 m/s
  • Time (t) = 12 s
  • Mass (m) = 200 Kg
  • Let the acceleration be a.
  • By using the equation of motion,

v = u + at, we have

  • 22 m/s = 10 m/s + 12 s × a
  • or, 22m/s - 10 m/s = 12 s × a
  • or, 12 m/s = 12 s × a
  • or, a = 1 m/s^2
  • Let the force be F.
  • We know, F = ma
  • Therefore, the force on the accelerated object (F)
  • = ma
  • = (200 × 1) N
  • = 200 N

<u>Answer</u><u>:</u>

<u>b)</u><u> </u><u>2</u><u>0</u><u>0</u><u> </u><u>N</u>

Hope you could understand.

If you have any query, feel free to ask.

4 0
2 years ago
Tom kicks a soccer ball on a flat, level field giving it an initial speed of 20 m/s at an angle of 35 degrees above the horizont
SVEN [57.7K]

Answer:

(a) 2.34 s

(b) 6.71 m

(c) 38.35 m

(d) 20 m/s

Explanation:

u = 20 m/s, theta = 35 degree

(a) The formula for the time of flight is given by

T = \frac{2 u Sin\theta }{g}

T = \frac{2 \times 20 \times Sin35 }{9.8}

T = 2.34 second

(b) The formula for the maximum height is given by

H = \frac{u^{2} \times Sin^{2}\theta }{2g}

H = \frac{20^{2} \times Sin^{2}35 }{2 \times 9.8}

H  = 6.71 m

(c) The formula for the range is given by

R = \frac{u^{2} \times Sin 2\theta }{g}

R = \frac{20^{2} \times Sin 2 \times 35}{9.8}

R = 38.35 m

(d) It hits with the same speed at the initial speed.

8 0
3 years ago
The percentage of incident light radiation reflected back to space is termed albedo. True or false?
liubo4ka [24]

Answer:True

Explanation:

Albedo is a unit-less, non-dimensional quantity that shows how well a surface reflects solar energy. The value of albedo can vary from 0 to 1, 0 being the black and 1 refers to a white surface. Zero means Surface is a perfect absorber i.e. it absorbs all the incoming rays incidents on it. Albedo 1 means the surface is a perfect reflector.

Albedo usually applies for visible light, even though it may involve some of the infrared regions of the electromagnetic spectrum. The average albedo associated with earth surface is 30%

8 0
3 years ago
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