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diamong [38]
4 years ago
8

What will happen to plant height if the amount of available light is reduced due to global dimming?

Physics
1 answer:
SpyIntel [72]4 years ago
7 0
The plants would wilt and decrease in height due to the lack of sunlight. I hope I helped!
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What characteristics distinguish the inner planets in the solar system from the outer planets?
Julli [10]
  • The four inner plants have shorter orbits slower spin ,no rings ,and they are made up of rock and metal
  • The outer plants are made up of hydrogen and helium, so they are called gas giants

Explanation:

hope it is the right answer

5 0
3 years ago
This isn’t homework related but what methods do you guys recommend for shifting realities ? .I’ve tried the raven method for wee
elena55 [62]

Answer:

subs

Explanation:

I've seen subliminals online that are supposed to help shifting. You could see for yourself if they work for you. You could probably also use the method where you act like you already have your desires and results. I have seen a lot of people act as if they have their desires and affirm it constantly. Ex: you want to lose weight, so you act as if you already are your desired weight and tell yourself that you are such and such weight, and don't contradict it by saying that you aren't. I hope that this helps.

6 0
3 years ago
A particle with charge − 2.74 × 10 − 6 C −2.74×10−6 C is released at rest in a region of constant, uniform electric field. Assum
s2008m [1.1K]

Answer:

241.7 s

Explanation:

We are given that

Charge of particle=q=-2.74\times 10^{-6} C

Kinetic energy of particle=K_E=6.65\times 10^{-10} J

Initial time=t_1=6.36 s

Final potential difference=V_2=0.351 V

We have to find the time t after that the particle is released and traveled through a potential difference 0.351 V.

We know that

qV=K.E

Using the formula

2.74\times 10^{-6}V_1=6.65\times 10^{-10} J

V_1=\frac{6.65\times 10^{-10}}{2.74\times 10^{-6}}=2.43\times 10^{-4} V

Initial voltage=V_1=2.43\times 10^{-4} V

\frac{\initial\;voltage}{final\;voltage}=(\frac{initial\;time}{final\;time})^2

Using the formula

\frac{V_1}{V_2}=(\frac{6.36}{t})^2

\frac{2.43\times 10^{-4}}{0.351}=\frac{(6.36)^2}{t^2}

t^2=\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}

t=\sqrt{\frac{(6.36)^2\times 0.351}{2.43\times 10^{-4}}}

t=241.7 s

Hence, after 241.7 s the particle is released has it traveled through a potential difference of 0.351 V.

6 0
3 years ago
A school bus takes 0.530 h to reach the school from your house. If the average velocity of the bus is 19.0 km/h to the east, wha
kifflom [539]

Answer:

x_{distance}=10.07km

Explanation:

Given data

time=0.530 h

Average velocity Vavg=19.0 km/s

To find

Displacement Δx

Solution

The Formula for average velocity is given as

V_{avg}=(x_{distance} )/(t_{time} )\\ x_{distance}=V_{avg}*(t_{time} )\\x_{distance}=(19.0km/h)*(0.530h)\\x_{distance}=10.07km

3 0
4 years ago
Happy Valentines Day<br><br> FR33 points for you guys
Fed [463]

Answer:

thankkkkkksssssssssssssss

6 0
3 years ago
Read 2 more answers
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