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diamong [38]
3 years ago
8

What will happen to plant height if the amount of available light is reduced due to global dimming?

Physics
1 answer:
SpyIntel [72]3 years ago
7 0
The plants would wilt and decrease in height due to the lack of sunlight. I hope I helped!
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When an object moves, where does the energy come from?
prisoha [69]

Answer:

potential energy cover in to kinetic energy

i hope it will work

3 0
3 years ago
What is the length of an aluminum rod at 65°C if its length at 15°C is 1.2 meters?
lana66690 [7]

<em><u>Answer:</u></em>

The new length is 1.20138 m

<em><u>Explanation:</u></em>

<u>1- We get the increase in length:</u>

The old length = 1.2 m

The coefficient of expansion of of aluminum is 23 * 10⁻⁶ /K.

The old temperature is 15°C.

The new temperature is 65°C

The increase in length= old length * coefficient of expansion *change in temperature

The increase in length = 1.2 * 23 * 10⁻⁶ * (65-15)

The increase in length = 0.00138 m

<u>2- getting the new length:</u>

new length = old length + increase in length

new length = 1.2 + 0.00138

new length = 1.20138 m

Hope this helps :)

3 0
3 years ago
Read 2 more answers
The lamp cord is 85cm long and comprises cupper wire. Calculate the wire‘s resistance?
DaniilM [7]

Answer:

R = 0.0015Ω

Explanation:

The formula for calculating the resistivity of a material is expressed as;

ρ = RA/l

R is the resistance

ρ is the resistivity

A is the area of the wire

l is the length of the wire

Given

l = 85cm = 0.85m

A = πr²

A = 3.14*0.0018²

A = 0.0000101736m²

ρ = 1.75 × 10-8Ωm.

Substitute into the formula

1.75 × 10-8 = 0.0000101736R/0.85

1.4875× 10-8 = 0.0000101736R

R = 1.4875× 10-8/0.0000101736

R = 0.0015Ω

3 0
3 years ago
A 675 kg car moving at 15.7 m/s hits from behind another car moving at 9.6 m/s in the same direction. If the second car has a ma
Maslowich

Answer:

?!?!?!?!?!?!

Explanation:

?!?!?!?!?!?!?

3 0
3 years ago
Ernest Rutherford (the first New Zealander to be awarded the Nobel Prize in Chemistry) demonstrated that nuclei were very small
Vaselesa [24]

Answer:

The final kinetic energy of the Helium nucleus (alpha particle) after been scattered through an angle of 120° is

8.00 x 10-13J

Explanation:

In Rutherford Scattering experiment, the collision of the helium nucleus with the gold nucleus is an ELASTIC COLLISION. This means that the kinetic energy is conserved ( The same before and after the collision).

Thus, the final kinetic energy of the helium nucleus is the same as initial kinetic energy (8.00 x 10^-13Joules)

Although, the kinetic energy is converted to potential energy in Coulomb's law equation.

That is,

1/2(mv^2) = (K* q1q2)/r

Where m is the mass of helium nucleus, v is its colliding velocity, k is electrostatic constant, q1 is the charge on helium nucleus, q2 is the charge on gold nucleus, r is impact parameter

6 0
3 years ago
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