Answer:
potential energy cover in to kinetic energy
i hope it will work
<em><u>Answer:</u></em>
The new length is 1.20138 m
<em><u>Explanation:</u></em>
<u>1- We get the increase in length:</u>
The old length = 1.2 m
The coefficient of expansion of of aluminum is 23 * 10⁻⁶ /K.
The old temperature is 15°C.
The new temperature is 65°C
The increase in length= old length * coefficient of expansion *change in temperature
The increase in length = 1.2 * 23 * 10⁻⁶ * (65-15)
The increase in length = 0.00138 m
<u>2- getting the new length:</u>
new length = old length + increase in length
new length = 1.2 + 0.00138
new length = 1.20138 m
Hope this helps :)
Answer:
R = 0.0015Ω
Explanation:
The formula for calculating the resistivity of a material is expressed as;
ρ = RA/l
R is the resistance
ρ is the resistivity
A is the area of the wire
l is the length of the wire
Given
l = 85cm = 0.85m
A = πr²
A = 3.14*0.0018²
A = 0.0000101736m²
ρ = 1.75 × 10-8Ωm.
Substitute into the formula
1.75 × 10-8 = 0.0000101736R/0.85
1.4875× 10-8 = 0.0000101736R
R = 1.4875× 10-8/0.0000101736
R = 0.0015Ω
Answer:
The final kinetic energy of the Helium nucleus (alpha particle) after been scattered through an angle of 120° is
8.00 x 10-13J
Explanation:
In Rutherford Scattering experiment, the collision of the helium nucleus with the gold nucleus is an ELASTIC COLLISION. This means that the kinetic energy is conserved ( The same before and after the collision).
Thus, the final kinetic energy of the helium nucleus is the same as initial kinetic energy (8.00 x 10^-13Joules)
Although, the kinetic energy is converted to potential energy in Coulomb's law equation.
That is,
1/2(mv^2) = (K* q1q2)/r
Where m is the mass of helium nucleus, v is its colliding velocity, k is electrostatic constant, q1 is the charge on helium nucleus, q2 is the charge on gold nucleus, r is impact parameter
