To do this, you would first add together the molar mass of all involved elements, to find how many grams are in a mole of Cu(OH)2. Keep in mind, the molar mass is equal to the atomic mass of an element in grams. For example the molar mass of copper (Cu) would be 63.55 (with 2 sig. figs.)
Therefore, now we add together the mass of all elements involved.
Cu: (63.55)+O2(15.99x2=31.98)+H2(1.01x2=2.02)
63.55+31.98+2.02= 97.55g per mole of Cu(OH)2.
Now, divide what we have by how much it takes to get a mole of the stuff.
68.1/97.55= 0.698mol Cu(OH)2
Answer : The enthalpy change for the reaction is, 97.7 kJ
Explanation :
According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.
According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.
The given main chemical reaction is,
The intermediate balanced chemical reaction will be,
(1) 
(2) 
(3) 
Now we are multiplying reaction 1 by 2 and reversing reaction 3 and then adding all the equations, we get :
(1) 
(2)
(3) 
The expression for enthalpy of main reaction will be,
Therefore, the enthalpy change for the reaction is, 97.7 kJ
Answer:
The answer is D. 0.60 L
Explanation:
The balanced reaction equation including states of matter is;
H₂SO₄(aq) + 2NaOH(aq) → Na₂SO₄(aq) + 2H₂O(l)
More simple:
H2SO4 + 2NaOH → Na2SO4 + 2H2O
Now, we can see from this reaction equation that the mole ratio of NaOH to H2SO4 is 2:1
Number of moles of H2SO4 reacted = 1.2 moles
Hence;
2 moles of NaOH reacts with 1 mole of H2SO4
x moles of NaOH reacts with 1.2 moles of H2SO4
x = 2 * 1.2/1 = 2.4 moles of NaOH
Recall that;
Number of moles = Concentration * Volume
Volume = number of moles/concentration
Volume of NaOH is obtained from;
Volume = 2.4 moles/ 4.0 M
Volume = 0.60 L
Answer:
378mL
Explanation:
The following data were obtained from the question:
Pressure (P) = 99.19 kPa
Temperature (T) = 28°C
Number of mole (n) = 0.015 mole
Volume (V) =...?
Next, we shall convert the pressure and temperature to appropriate units. This is illustrated below:
For Pressure:
101.325 KPa = 1 atm
Therefore, 99.19 kPa = 99.19/101.325 = 0.98 atm
For Temperature:
T(K) = T(°C) + 273
T(°C) = 28°C
T(K) = 28°C + 273 = 301K.
Next we shall determine the volume of N2. The volume of N2 can be obtained by using the ideal gas equation as shown below:
PV = nRT
Pressure (P) = 0.98 atm
Temperature (T) = 301K
Number of mole (n) = 0.015 mole
Gas constant (R) = 0.0821atm.L/Kmol.
Volume (V) =...?
0.98 x V = 0.015 x 0.0821 x 301
Divide both side by 0.98
V = (0.015 x 0.0821 x 301) /0.98
V = 0.378 L
Finally, we shall convert 0.378 L to millilitres (mL). This is illustrated below:
1L = 1000mL
Therefore, 0.378L = 0.378 x 1000 = 378mL
Therefore, the volume of N2 collected is 378mL
