What amount if force need to be applied to a 20 kg bowling ball to give it an acceleration of 5m/s

What volume of O2 collected at 22.0 and 728 mmHg would be produce by the decomposition of 8.15 g KClO3?

adell [148]

Answer:

There is 2.52 L of O2 collected

Explanation:

Step 1: Data given:

Temperature = 22.0 °C

Pressure = 728 mmHg = 728 /760 = 0.958 atm

Mass of KClO3 = 8.15 grams

Molar mass of KClO3 = 122.55 g/mol

Step 2: The balanced equation

2KClO3(s) → 2KCl(s) + 3O2(g)

Step 3: Calculate moles of KClO3

Moles KClO3 = mass KClO3 / molar mass KClO3

Moles KClO3= 8.15 grams / 122.55 g/mol

Moles KClO3 = 0.0665 moles

Step 4: Calculate moles of O2

For 2 moles of KClO3 we'll have 2 moles of KCl and 3 moles of O2 produced

For 0.0665 moles of KClO3 we have 3/2 * 0.0665 = 0.09975 moles

Step 5: Calculate vlume of O2

p*V = n*R*T

V = (n*R*T)/p

⇒ with n = the number of moles O2 = 0.09975 moles

⇒ with R = the gas constant = 0.08206 L*atm/K*mol

⇒ with T = 22.0 °C = 273 +22 = 295 Kelvin

⇒ with p = 0.958 atm

V = (0.09975 * 0.08206 * 295) / 0.958

V = 2.52 L

There is 2.52 L of O2 collected

7 0

3 years ago

How many moles of oxygen are present in 16 g of oxygen gas

makkiz [27]

Hope this helps

Answer- 1 mole

4 0

3 years ago

Read 2 more answers

If 72.5 grams of calcium metal (Ca) react with 65.0 grams of oxygen gas (O2) in a synthesis reaction, how many grams of the exce

Natali5045456 [20]

2Ca + O2 = 2CaO
First, determine which is the excess reactant
72.5 g Ca (1 mol) =1.8089725036
(40.078 g)

65 g O2 (1 mol) =2.0313769611
(15.999g × 2)
Since the ratio of to O2 is 2:1 in the balanced reaction, divide Ca's molar mass by 2 to get 0.9044862518. this isn't necessary because Ca is already obviously the limiting reactant. therefore, O2 is the excess reactant.

Now do the stoichiometry
72.5 g Ca (1 mol Ca) (1 mol O2)
(40.078 g Ca)(2 mol Ca)(31.998g O2)

=0.0282669621 g of O2 left over

5 0

3 years ago

Which statement best explains why mass is not conserved in a nuclear change?

kogti [31]

Answer:

Mass in nuclear reactions is not strictly conserved due to this principle of mass and energy being quite similar. We know that nuclear reactions release a lot of energy. This energy, though, is actually mass that is lost from nucleons, converted into energy, and lost as the mass defect.

Some mass is turned into energy, according to E=mc2.

<em><u>Explanation:</u></em>

E=mc2 is probably the most famous equation. E is the energy, m is mass, and c is the constant speed of light. Einstein came up with it to show that energy and mass are proportional - one can turn into the other, and back again.

Mass in nuclear reactions is not strictly conserved due to this principle of mass and energy being quite similar. We know that nuclear reactions release a lot of energy. This energy, though, is actually mass that is lost from nucleons, converted into energy, and lost as the mass defect.

5 0

2 years ago

You are given 10ml (M) 20 Naoh solution in a conical flask and asked to titrate with (M) 20 Hcl and (M) 20 H2so4 separately. cal

Solnce55 [7]

Answer:

$n_{HCl}=0.2molHCl\\n_{H_2SO_4}=0.1molH_2SO_4$

Explanation:

Hello!

In this case, since the reactions between NaOH and the acids are:

$NaOH+HCl\rightarrow NaCl+H_2O\\\\2NaOH+H_2SO_4\rightarrow Na_2SO_4+2H_2O$

Whereas we can see the 1:1 and 2:1 mole ratios between NaOH and HCl and H2SO4 respectively. In such a way, at the equivalence point we realize that:

$n_{HCl}=n_{NaOH}=V_{NaOH}M_{NaOH}=0.01L*20mol/L=0.2molHCl\\\\2n_{H_2SO_4}=n_{NaOH}\\\\n_{H_2SO_4}=\frac{1}{2} V_{NaOH}M_{NaOH}=\frac{0.01L*20mol/L}{2} =0.1molH_2SO_4$

Best regards!

8 0

3 years ago