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3 years ago

Please Help!!!!!

Physics

1 answer:

Oliga [24]3 years ago

3 0

Answer: Molecules of H202, H20 and 02 are still forming. ( A P E X )

Explanation: I know this is late but for anyone looking at this later

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According to the law of conservation of momentum, the ____________________ amount of momentum of a group of objects does not cha

erica [24]

According to the law of conservation of momentum, the TOTAL amount of momentum of a group of objects does not change unless outside _____FORCES____ act on the objects.

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3 years ago

One recently discovered extrasolar planet, or exoplanet, orbits a star whose mass is 0.70 times the mass of our sun. This planet

Stels [109]

0.078 times the orbital radius r of the earth around our sun is the exoplanet's orbital radius around its sun.

Answer: Option B

Explanation:

Given that planet is revolving around the earth so from the statement of centrifugal force, we know that any

$\frac{G M m}{r^{2}}=m \omega^{2} r$

The orbit’s period is given by,

$T=\sqrt{\frac{2 \pi}{\omega r^{2}}}=\sqrt{\frac{r^{3}}{G M}}$

Where,

$T_{e}$ = Earth’s period

$T_{p}$ = planet’s period

$M_{s}$ = sun’s mass

$r_{e}$ = earth’s radius

Now,

$T_{e}=\sqrt{\frac{r_{e}^{3}}{G M_{s}}}$

As, planet mass is equal to 0.7 times the sun mass, so

$T_{p}=\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}$

Taking the ratios of both equation, we get,

$\frac{T_{e}}{T_{p}}=\frac{\sqrt{\frac{r_{e}^{3}}{G M_{s}}}}{\sqrt{\frac{r_{p}^{3}}{0.7 G M_{s}}}}$

$\frac{T_{e}}{T_{p}}=\sqrt{\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}}$

$\left(\frac{T_{e}}{T_{p}}\right)^{2}=\frac{0.7 \times r_{e}^{3}}{r_{p}^{3}}$

$\left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}=\frac{r_{e}^{3}}{r_{p}^{3}}$

$\frac{r_{e}}{r_{p}}=\left(\left(\frac{T_{e}}{T_{p}}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}$

Given $T_{p}=9.5 \text { days }$ and $T_{e}=365 \text { days }$

$\frac{r_{e}}{r_{p}}=\left(\left(\frac{365}{9.5}\right)^{2} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=\left(\frac{133225}{90.25} \times \frac{1}{0.7}\right)^{\frac{1}{3}}=(2108.82)^{\frac{1}{3}}$

$r_{p}=\left(\frac{1}{(2108.82)^{\frac{1}{3}}}\right) r_{e}=\left(\frac{1}{12.82}\right) r_{e}=0.078 r_{e}$

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2 years ago

Fill in the blanks HELP ASAP

Alexandra [31]

checking to see if im locked out

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3 years ago

Becquerel thought that ____ was necessary for minerals to give to give off energy that passed through paper?

Annette [7]

B sunlight, because the sun has energy and that gives the soil energy and the plant take that energy and is able to grow.

5 0

3 years ago

Field lines in an Magnetic field

finlep [7]

The lines of magnetic field starts from North and terminates in the South direction outside the magnet and from South to North inside.

Explanation:

The imaginary lines that are drawn to represent the direction and strength of magnetic field is known as magnetic field lines. The magnetic field direction remains "tangent to magnetic field line". These magnetic field lines never intersect (the magnetic field is distinctive at any point).

The density of the lines decreases when they travel from higher permeability area to lower permeability area. All the field lines have same strength. They are closed lines i.e. they always form the closed loops. By this, we can represent that the field flows from North to South Pole from outward.

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2 years ago