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Inessa [10]
3 years ago
12

The temperature, T, of a gas is jointly proportional to the pressure P of the gas and the volume V occupied by the gas. Use C as

your proportionality constant. (a) Express the temperature in terms of the pressure and the volume.
Physics
1 answer:
AnnZ [28]3 years ago
3 0

Answer:

T=C*P*V

Explanation:

It is said that a variable - let's call 'y' -, is proportional to another - let's call it 'x' - if x and y are multiplicatively connected to a constant 'C'. It means that their product (x*y) can be always equaled to the constant 'C' or their division (\frac{x}{y}) can be always equaled to 'C'. The first case is the case of the inverse proportionality: It is said that x and y are inversely proportional if

x*y=C

The second case is the case of the direct proportionality: It is said that x and y are directly proportional if

\frac{x}{y} =C : x is directly proportional to y.

or

\frac{y}{x} =C : y is directly proportional to x.

Always that any text does not specify about directly or inversely proportionality, it is assumed to mean directly automatically.

For our case, we are said that the temperature T is proportional to the pressure P and the volume V (we assume that it means directly); it is a double proportionality but follows the same rules:

If T were just proportional to P, we would have:

\frac{T}{P} =C

If T were just proportional to V, we would have:

\frac{T}{V} =C

As T is proportional to both P and V, the right equation is:

\frac{T}{P*V}=C

In order to isolate the temperature, let's multiply (P*V) at each side of the equation:

\frac{T}{P*V}*(P*V)=C*(P*V)\\T=C*P*V

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The bright yellow light emitted by a sodium vapor lamp consists of two emission lines at 589.0 and 589.6 nm. What are the freque
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Explanation:

Given

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Energy is given by

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x=velocity of Light

\lambda=wavelength of emission

E_1=\frac{6.626\times 10^{-34}\times 3\times 10^8}{589\times 10^{-9}}

E_1=3.374\times 10^{-19} J

E_1 in kJ/mol

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frequency corresponding to this emission

\nu =\frac{c}{\lambda }

\nu _1=\frac{3\times 10^8}{589\times 10^{-9}}

\nu _1=5.09\times 10^{14} Hz

Energy corresponding to \lambda _2

E_2=\frac{6.626\times 10^{-34}\times 3\times 10^8}{589.6\times 10^{-9}}

E_2=3.371\times 10^{-19} J

E_2=203.02 kJ/mol

frequency corresponding to this emission

\nu =\frac{c}{\lambda }

\nu _1=\frac{3\times 10^8}{589.6\times 10^{-9}}

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What is the kinetic energy of a 150 gram object moving at a velocity of 100 m/s?
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2 years ago
the density of aluminum is 2700 kg/m3. if transverse waves travel at in an aluminum wire of diameter what is the tension on the
Sunny_sXe [5.5K]

The tension on the wire is 52.02 N.

From the question, we have

Density of aluminum = 2700 kg/m3

Area,

A = πd²/4

A = π x (4.6 x 10⁻³)²/4

A = 1.66 x 10⁻⁵ m²

μ = Mass per unit length of the wire

μ = ρA

μ = 2700 kg/m³ x 1.66 x 10⁻⁵ m²

μ = 0.045 kg/m

Tension on the wire = √T/μ

34 = √T/0.045

34² = T/0.045

T = 52.02 N

The tension on the wire is 52.02 N.

Complete question:

The density of aluminum is 2700 kg/m3. If transverse waves propagate at 34 m/s in a 4.6-mm diameter aluminum wire, what is the tension on the wire.

To learn more about tension visit:  brainly.com/question/14336853

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