40 km/h to in/s
60*60=3600 seconds in an hour
one km is about 0.621 miles
40 km is about 0.621*40=24.84 miles
5280 feet in a mile
12 inches on each foot
5280*12=63360 inches in a mile
63360*24.84=1573862.4 inches in 40km
40 km/h = 40*1573862.4/3600=17487.36 in/s
'Pressure' is (force) / (area).
The only choice with those units is #1 .
Answer:
18000 J
Explanation:
From the question given above, the following data were obtained:
At point 4:
Mass of cart = 600 Kg
Velocity of cart (v) = 7.745 m/s
Kinetic energy (KE) =?
KE = ½mv²
KE = ½ × 600 × 7.745²
KE = 300 × 7.745²
KE ≈ 18000 J
Therefore, the mechanical energy of the cart at point 4 is 18000 J
when the aim is to show electron distributions in shells.
hope this helps :)
We assume that the gas is an ideal gas so we can use the relation PV=nRT. Assuming that the temperature of the system is at ambient temperature, T = 298 K. We can calculate as follows:
PV = nRT
P = nRT / V
P = (0.801 mol ) (0.08205 L-atm / mol-K) (298.15 K) / 12 L
P = 1.633 atm
