Answer: a. ![H_2AsO_4^{-}(aq)+H_2O(l)\rightarrow HAsO_4^{2-}(aq)+H_3O^+(aq)](https://tex.z-dn.net/?f=H_2AsO_4%5E%7B-%7D%28aq%29%2BH_2O%28l%29%5Crightarrow%20HAsO_4%5E%7B2-%7D%28aq%29%2BH_3O%5E%2B%28aq%29)
b. ![K_a=\frac{[HAsO_4^{2-}]\times [H_3O^+]}{[H_2AsO_4^{-}]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BHAsO_4%5E%7B2-%7D%5D%5Ctimes%20%5BH_3O%5E%2B%5D%7D%7B%5BH_2AsO_4%5E%7B-%7D%5D%7D)
Explanation:-
According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.
The balanced chemical equation is:
![H_2AsO_4^{-}(aq)+H_2O(l)\rightarrow HAsO_4^{2-}(aq)+H_3O^+(aq)](https://tex.z-dn.net/?f=H_2AsO_4%5E%7B-%7D%28aq%29%2BH_2O%28l%29%5Crightarrow%20HAsO_4%5E%7B2-%7D%28aq%29%2BH_3O%5E%2B%28aq%29)
Here,
is loosing a proton, thus it is considered as an acid and after losing a proton, it forms
which is a conjugate base.
And,
is gaining a proton, thus it is considered as a base and after gaining a proton, it forms
which is a conjugate acid.
The dissociation constant is given by:
![K_a=\frac{[HAsO_4^{2-}]\times [H_3O^+]}{[H_2AsO_4^-]}](https://tex.z-dn.net/?f=K_a%3D%5Cfrac%7B%5BHAsO_4%5E%7B2-%7D%5D%5Ctimes%20%5BH_3O%5E%2B%5D%7D%7B%5BH_2AsO_4%5E-%5D%7D)
She will use the periodic table of elements to not only find out the chemical symbols of the elements written within the name, but also to check whether or not the elements are metals and or nonmetals, from this determine the ionic charges if needed for metals, and for metals that have more than one ionic charge, use a Roman numeral to represent the ionic charge that she would be using in writing the chemical formula of the compound.
Answer:
P2>S2>Cl2 is the order of bond energy of the given molecules.
Explanation:
The bonding in each molecule is shown below:
Thus, between each P-atom, there exists a triple bond.
Between two S-atoms there exists a double bond.
Between two chlorine atoms, there exists a single bond.
As the number of bonds increases between the given atoms, then bond energy required to break the bonds also increases.
Thus, the bond order is shown below:
.
The
chemical reaction is represented as:<span>
2A(g) = B(g) + C(g)
To determine the equilibrium concentration of A, we make use of the equilibrium
constant, Kc, given above. It is expressed as the ratio of the equilibrium
concentrations of the products and the reactants. For this reaction, it is
expressed as:
Kc = [B] [C] / [A]^2
From the problem statement, we are given the following
Kc = 0.035
Volume = 20.0 L
Initial concentrations: [B] = 8.00 mol / 20.0 L = 0.4 M
[C] = 12.00 mol / 20.0 L = 0.6
M
Since the initial reactants are B and C, the reaction is reversed as well as
the Kc.
Kc = [A]^2 / [B][C]
We use the ICE table:
B
C A
I 0.4 0.6
0
C -x -x
+x
------------------------------------------
E 0.4 - x 0.6 - x
x
Kc = x^2 / (0.4-x) (0.6-x) = 0.035
solve for x,
x = 0.07691 = [A]</span>
D i had taken the test already.