Dear friend,
How are you doing? I finally switched to my new school and it's been so hard adjusting. But I know I have a new chance at making new friends and memories. Also, I can learn new things, like interacting with new people and how to keep my anxiety low. I really miss us hanging out and how much we'd laugh and get in trouble at class. But i really hope to see you soon & that it hasn't gone terribly wrong for you since i left.
your friend,
name
an element's name, chemical symbol, atomic number, atomic mass.
IDK what you are even asking for
Answer:
0.00011765 M
Explanation:
When a solution is prepared by dilution, the volumes and concentrations are related by:
C1*V1 = C2*V2
Where C1 is the concentration of the solution 1, V1 is the volume of the solution 1, C2 is the concentration of solution 2, and V2 is the volume of solution 2.
The stock solution is the solution 1, and the standard solution, the solution 2, so:
0.0001974*29.80 = C2*50.00
C2 = 0.00011765 M
Answer:
Its B
Explanation:
Products <=> reactants; products can go back to reactant and reactants can form products, depending on the equilibrium position.
The equilibrium position, if it is on the left, and much of the product is formed. If the equilibrium position is not the right, then its the vice versa The equilibrium position is determined by ;
- <em><u>Temperature</u></em>
If the reaction is endothermic, it will be favoured by increase in temperature and equilibrium position will shift to the right ( reactants )
If the reaction is exothermic, its the vice versa
<em><u>N</u></em><em><u>O</u></em><em><u>T</u></em><em><u>E</u></em><em><u>:</u></em><em><u> </u></em>Only temperature affects the equilibrium position
Answer:
For these problems, we need to compare the theoretical yield that we'd get from performing stoichiometry to the actual yield stated in the problem. % yield is the actual yield/theoretical yield x 100%
Cu + 2 AgNO₠→ Cu(NOâ‚)â‚‚ + 2 Ag ==> each mole of copper yields two moles of silver
12.7-g Cu x ( 1 mol Cu /63.5-g Cu) x ( 2 mol Ag / 1 mol Cu) x (108-g Ag / 1 mol Ag) = 43.2-g Ag. This is the theoretical yield. Now, since we got 38.1-g Ag our % yield is:
38.1-g/43.2-g x 100% = 88.2%
Explanation:
