Answer:
The older scientist were ignorant
Explanation:
they thought that they were better than the younger scientist. to put it in simply they were ignorant to think younger is worse
Answer: 
, 
and 
are formed at the end of the reaction. They are named as tin (IV) oxide or stannic oxide, nitrogen dioxide and water respectively.
Explanation: Reaction of tin and nitric acid is given as:
Three products are formed at the end of the reaction which are:
- which is termed as stannic oxide or Tin (IV) oxide. This is a white colored solid.
- which is termed as nitrogen dioxide. These are brown colored fumes.
- which is termed as water.
At the starting tin was a silvery-white colored solid and after the reaction, it changed the color to milky-white. This change in color is due to the chemical reaction happening between tin and nitric acid.
Release of brown fumes are also an indication that a chemical reaction has taken place.
Answer: When using 645 L /s of O2 in a temperature and pressure of 195°C, 0.88 atm respectively, we will get 0.355Kg /s NO
Explanation:
- First we review the equation that represents the oxidation process of the NH3 to NO.
4NH3(g) + 5O2(g) ⟶4 NO(g) +6 H2O(l)
- Second we gather the information what we are going to use in our calculations.
O2 Volume Rate = 645 L /s
Pressure = 0.88 atm
Temperature = 195°C + 273 = 468K
NO molecular weight = 30.01 g/mol
- Third, in order to calculate the amount of NO moles produced by 645L/ s of O2, we must find out, how many moles (n) are 645L O2 by using the general gas equation PV =n RT
Let´s keep in mind that using this equation our constant R is 0.08205Lxatm/Kxmol
PV =n RT
n= PV / RT
n= [ 0.88atm x 645L/s] / [ (0.08205 Lxatm/Kxmol) x 468K]
n= 14.781 moles /s of O2
-
Fourth, now by knowing the amount of moles of O2, we can use the equation to calculate how many moles of NO will be produced and then with the molecular weight, we will finally know the total mass per second .
14.781 moles /s of O2 x 4moles NO / 5 moles O2 x 30.01g NO / 1 mol NO x 1Kg NO /1000g NO = 0.355Kg /s NO
Each mole of N₂ generates 2 moles of Li₃N. Thus,
0.08 moles of Li₃N will require:
0.08 / 2
= 0.04 moles of N₂
The second option is correct.
