Concave mirrors, magnifying lens... sorry not sure about the rest
The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Data;
- Volume of solution = 260mL
- conc. of HCHO2 = 2.5*10^-2M
- conc. of NaCHO2 = 2.5*10^-2M
<h3>Mass of Reagent Added</h3>
To calculate the mass of reagent added, let's start with HCHO2
The mass of HCHO2 to be added is the number of moles of HCHO2 multiplied by it's molar mass.

The mass of NaCHO2 to be added in the buffer solution is

The mass of HCHO2 and NaCHO2 to be added to the buffer solution are 0.23g and 0.44g respectively
Learn more about buffer solution here;
brainly.com/question/22390063
Answer:
3.213J/mol
Explanation:
first specific heat capacity of water = 4200J/Kg K
Q=mass×temperature difference×specific heat capacity
Q=1.53×(24.3-20)×4200
Q=25.704 J
heat of solution= quantity of heat ÷ amount of substance
heat of solution= 25.704÷8
heat of solution= 3.213J/mol
In the balanced reaction shown, there are twice as many moles of water as oxygen. If 13.35 moles of oxygen are reacted, 26.70 moles of water is formed
Answer:
A to show that the mass of atoms in the product