Answer:
The mass of the block of ice is 90.91 kg.
Explanation:
The expression for the equation of motion is as follows;
![s=ut+\frac{1}{2}at^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2)
Here, u is the initial speed, a is the acceleration, t is the time and s is the distance.
Calculate the acceleration of the given block.
![s=ut+\frac{1}{2}at^2](https://tex.z-dn.net/?f=s%3Dut%2B%5Cfrac%7B1%7D%7B2%7Dat%5E2)
Put t= 5 s, s= 11 m and u= 0 in the above expression.
![11=(0)t+\frac{1}{2}a(5)^2](https://tex.z-dn.net/?f=11%3D%280%29t%2B%5Cfrac%7B1%7D%7B2%7Da%285%29%5E2)
![a= 0.88 ms^{-2}](https://tex.z-dn.net/?f=a%3D%200.88%20ms%5E%7B-2%7D)
The expression for the force in terms of mass and acceleration is as follows;
F= ma
Here, F is the force and m is the mass.
Put F= 80 N and
.
80= m(0.88)
m=90.91 kg
Therefore, the mass of the block of ice is 90.91 kg.
Answer:
E0
Explanation:
Yes. The "0" indicates that it is spherical