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2 years ago

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Chemistry

1 answer:

Vilka [71]2 years ago

6 0

The period is the end of the sentence!!!

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When the following equation is balanced using the smallest possible integers, what is the number in front of the substance in bo

weeeeeb [17]

The balanced equation :

8Al + 3Fe₃O₄→ 4Al₂O₃ + 9Fe

You just have to look for which element is in bold because the question is not clear

<h3>Further explanation</h3>

Equalization of chemical reaction equations can be done using variables. Steps in equalizing the reaction equation:

1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c etc.

2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index between reactant and product

3. Select the coefficient of the substance with the most complex chemical formula equal to 1

Reaction

Al + Fe₃O₄→ Al₂O₃ + Fe

give a coefficient

aAl + Fe₃O₄→ bAl₂O₃ + cFe

O, left=4, right=3b⇒3b=4⇒b=4/3

Al, left=a, right=2b⇒a=2b⇒a=2.4/3⇒a=8/3

Fe, left=3, right=c⇒c=3

The equation becomes :

8/3Al + Fe₃O₄→ 4/3Al₂O₃ + 3Fe x3

8Al + 3Fe₃O₄→ 4Al₂O₃ + 9Fe

7 0

3 years ago

What is the atomic mass number of an isotope that has an atomic number of 5 and includes 6 neutrons?

irinina [24]

The answer should be; 11

The atomic mass number is found by combining the number of protons and neutrons

Hope this helps :)

8 0

2 years ago

Read 2 more answers

Provided is a diagram showing forces on a box.

Eduardwww [97]

Answer:

5 N left

Explanation:

trust me cccuuhh

4 0

2 years ago

What is the systematic name of the following compound?<br> Li2S

Nuetrik [128]

Answer:

the systematic name is called Lithium sulfide.

6 0

2 years ago

The half life of carbon is 5,730 years. What fraction of the original 14/6 C would be in a wooden axe handle that was 17,190 yea

Mariana [72]

Answer:

$\frac{1}{8}$

Explanation:

The half-life of carbon (5730 y) is the time it takes for half the carbon to decay.

After one half-life, half (50 %) of the original amount will remain.

After a second half-life, half of that amount (25 %) will remain, and so on.

$\text{17 190 y} \times \frac {\text {1 half-life}}{\text{5730 y}} = \text{3 half-lives}$

We can construct a table.

<u>No of half-lives</u> <u>Fraction remaining</u>

1 $\frac{1}{2}$

2 $\frac{1}{4}$

3 $\frac{1}{8}$

The general formula is

$\text{Fraction remaining} = \frac{1}{2^{n}}$

where <em>n</em> = the number of half-lives.

Thus, $\frac{1}{8}$ of the original carbon remains after 17 190 y.

8 0

3 years ago