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vagabundo [1.1K]
3 years ago
11

Why is NaNO3 a homogenous mixture

Chemistry
1 answer:
wlad13 [49]3 years ago
6 0
Every pure compound is homogeneous...
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Someone please help me figure out the significant figure
Neporo4naja [7]
I believe the answer is 15kg since after that there is 16kg and before there is 14kg
4 0
1 year ago
What is the speed of a horse in meters per second that runs a distance of 1.2 miles in 2.4 minutes? (Hint: 1 mile = 1609 m)
dezoksy [38]
Time t=2.4 minutes=2.4×60=144 seconds
distance s=1.2 miles=1.2×1609=1930.8 meters
speed v=s/t=1930.8÷144=[tex] \frac{1930.8}{144} = \frac{160.9}{12} =[/13.408m/s ~nearly]
7 0
4 years ago
How many hydrogen grams can be obtained if
kipiarov [429]

hi im breanna

Answer:

The mole is simply a very large number that is used by chemists as a unit of measurement.

Explanation:

The mole is simply a very large number,  

6.022

×

10

23

, that has a special property. If I have  

6.022

×

10

23

hydrogen atoms, I have a mass of 1 gram of hydrogen atoms . If I have  

6.022

×

10

23

 

H

2

molecules, I have a mass of 2 gram of hydrogen molecules. If I have  

6.022

×

10

23

 

C

atoms, I have (approximately!) 12 grams.

The mole is thus the link between the micro world of atoms and molecules, and the macro world of grams and litres, the which we can easily measure by mass or volume. The masses for a mole of each element are given on the periodic table as the atomic weight. So, if have 12 g of  

C

, I know, fairly precisely, how many atoms of carbon I have. Given this quantity, I know how many molecules of  

O

2

are required to react with the  

C

, which I could measure by mass or by volume.

5 0
3 years ago
2. Calculate the mass of 5.35 mole of H2O2.
Dmitry_Shevchenko [17]

Answer:

5.35m H2O2 x 34.02g/1m H2O2 = 182g H2O2

Explanation:

6 0
3 years ago
Dr. House took two liquids of different densities (p_1=1500 kg/m^3; p_2 = 500 kg/m^3) are poured together into a 0.1 m^3 tank fi
SVETLANKA909090 [29]
We know that:
mass = density x volume
The volume of the total mixture is 0.1 m³
Let the first liquid be A and the second be B
Mass Total = Mass A + Mass B

800 x 0.1 = 1500Va + 500(0.1 - Va)
30 = 1000Va
Va = 0.03 m³
Vb = 0.1 - 0.03 = 0.07 m³
6 0
4 years ago
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