Answer:
C
Step-by-step explanation:
Distribute x^2 to 2x and 5, you’ll get 2x^3+5x^2.
The distribute 3 to 2x and 5, you’ll get 6x+15.
You’ll get what the question is asking for.
Step-by-step explanation:
cos A = 16/20 = 4/5
tan A = 12/16 = 3/4
sin A = 12/20 = 3/5
Answer:
C 160
Step-by-step explanation:
hop it helped you in any way
Answer:
I'm taking an educated guess here and saying that its option two.
I haven't done these problems in almost two years.
Answer:
A. b(w) = 80w +30
B. input: weeks; output: flowers that bloomed
C. 2830
Step-by-step explanation:
<h3>Part A:</h3>
For f(s) = 2s +30, and s(w) = 40w, the composite function f(s(w)) is ...
b(w) = f(s(w)) = 2(40w) +30
b(w) = 80w +30 . . . . . . blooms over w weeks
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<h3>Part B:</h3>
The input units of f(s) are <em>seeds</em>. The output units are <em>flowers</em>.
The input units of s(w) are <em>weeks</em>. The output units are <em>seeds</em>.
Then the function b(w) above has input units of <em>weeks</em>, and output units of <em>flowers</em> (blooms).
__
<h3>Part C:</h3>
For 35 weeks, the number of flowers that bloomed is ...
b(35) = 80(35) +30 = 2830 . . . . flowers bloomed over 35 weeks
