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3 years ago

What was the purpose of doing a rough sketch?

2 answers:

4 0

The purpose of doing a rough draft of any art, or project is to make the mistakes early. A rough draft usually does not count for points but it could depending on the project. It is like a pre-test sheet that allows you to realize or draw the mistakes at first hand and then finalize/fix them when you do the final draft.

I hope this helps!

galina1969 [7]3 years ago

3 0

To come up with an idea of what you want,and in case you want to change it during the process.

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What is the part of the racquet directly below the head that connects the head to the handle?

4vir4ik [10]

It's called Throat. You can refer the figure attached.

7 0

4 years ago

Car enthusiasts often lower their cars closer to the ground as a matter of style. James wants to lower his car by replacing all

Alexandra [31]

Answer:

$\Delta h=0.0364\ m=3.64\ cm$

Explanation:

Given:

change in stiffness constant of the spring on replacing the original springs, $\delta k=5355\ N.m^{-1}$

mass of the car, $m=1455\ kg$

initial length of the original car-spring before compression, $l_i=12\ cm=0.12\ m$

final length of the original car-spring after compression, $l_f=8.55\ cm=0.0855\ m$

So, weight of the car:

$w=m.g$

$w=1455\times 9.81$

$w=14273.55\ N$

Now the spring constant of original spring:

$w=4k_o.(l_i-l_f)$ (since 4 springs are in parallel)

$14273.55=4k_o\times (0.12-0.0855)$

$k_o=103431.522\ N.m^{-1}$

So the stiffness constant of the new springs:

$k_n=k_o-\delta k$

$k_n=103431.522-5355$

$k_n=98076.522\ N.m^{-1}$

Now the height lowered:

$w=k_n.4\Delta h$ (since 4 springs are in parallel)

$14273.55=4\times98076.522\times \Delta h$

$\Delta h=0.0364\ m=3.64\ cm$

5 0

4 years ago

The intensity of sunlight under the clear sky is 1160 w/m2 . how much electromagnetic energy is contained per cubic meter near t

Reil [10]

Answer:

= 3.869 × 10^-6 J/m³

Explanation:

Intensity is given as W/m^2 which is equivalent to J/ (s*m^2)

Speed of light is 2.99792 × 10^8 m/s.

Therefore;

Electromagnetic energy per cubic meter = Intensity/speed of light

= 1160 J/ (s*m³)/ 2.99792 × 10^8 m/s.

= 3.869 × 10^-6 J/m³

5 0

3 years ago

an object of mass 4 kg is placed on an inclined plane at an angle of 60. if the object slides down the plane with an acceleratio

balandron [24]

The forces on the y axis are:

N-mgcos(60)=0 , wich becomes

N=mgcos(60)

Rember that the friction force is always contrary to the motion of an object and its formula is f=μ * N

The forces in the x axis are:

-f + mgsin(60)= m * a

-μ*mgcos(60) + mgsin(60)=m*a ,

μ = ( m*a - mgf=μ[sin(60) )/ ( mgcos(90) )

6 0

3 years ago

PLEASE HELP! 3 Questions, 10 points a question, will give brainliest.

Basile [38]

1) Mechanical energy is conserved in all the 4 situations

2) True

3) The potential energy of the block is 490 J

Explanation:

Mechanical energy is the sum of potential energy (PE) and kinetic energy (KE) of a body:

$E=PE+KE$

According to the law of conservation of energy, in absence of non-conservative forces (such as air resistance, friction...), the mechanical energy of a body is always conserved.

This means that the mechanical energy is conserved in all the situations described. More specifically:

- Child on a swing : there is a continuous conversion between kinetic energy and gravitational potential energy

- Pendulum : there is a continuous conversion between kinetic energy and gravitational potential energy

Bow and Arrow : there is a conversion of energy from elastic potential (when the bow is stretched) to kinetic energy (when the arrow is shot)

Roller Coaster: there is a continuous conversion between kinetic energy and gravitational potential energy

As we said, the mechanical energy of the object falling down at any point of the fall is

$E=KE+PE$

where KE is the kinetic energy and PE is the potential energy. The value of E is constant, since the mechanical energy is conserved.

The potential energy is given by

$PE=mgh$

where m is the mass of the object, g is the acceleration of gravity, h is the height of the object above the ground.

As the object falls, its height $h$ decreases, and therefore, the potential energy PE also decreases. But we said that E must remain constant: therefore, if PE decreases, this means that KE increases, therefore as the object falls, the potential energy is converted into kinetic energy (in fact, the speed of the object increases). So the statement is true.