Answer:
Answered
Explanation:
Part A
According to Faraday's law the induced emf in coil is equal to negative of its rate of change of magnetic flux time the number of turns in the coil.
= 
When an emf generated by a change of magnetic flux, produced current of whose magnetic field opposes the change which produces it.
By the above equation the correct options are 1,2 and 4
Part B
Large signals of frequency of 60Hz are measured by osciloscope.
Hence the correct option is part 1.
Answer:
5.634 N rightwards
Explanation:
qo = - 3 x 10^-7 C
q1 = - 9 x 10^-6 C
q2 = 10 x 10^-6 C
r1 = 7 cm = 0.07 m
r2 = 20 cm = 0.2 m
The force on test charge due to q1 is F1 which is acting towards right
According to the Coulomb's law

F1 = (9 x 10^9 x 9 x 10^-6 x 3 x 10^-7) / (0.07 x 0.07)
F1 = 4.959 N rightwards
The force on test charge due to q2 is F1 which is acting towards right
According to the Coulomb's law

F2 = (9 x 10^9 x 10 x 10^-6 x 3 x 10^-7) / (0.2 x 0.2)
F2 = 0.675 N rightwards
Net force on the test charge
F = F1 + F2 = 4.959 + 0.675 = 5.634 N rightwards
Answer:
P= 15A x 120 V P= 1800 W
I believe, I hope this helps
Explanation:
Answer:
2084 kg*m/s
Explanation:
Impulse is change in momentum
Mathematically;
Impulse, J= F*t=mΔv where
F= ma = 1500 * { 30.56 - 16.67}/2*60
F= 1500 *0.11575
F= 174 N
J=F*t
J= 174*120*0.1
J= 2084 kg*m/s
Answer:
6.65m/s
Explanation:
Using the equation of motion
S = ut + 1/2gt²
S is the height of fall
t is the time
u is the horizontal velocity
g is the acceleration due to gravity
Given
S = 300 + 50
S = 350m
t = 7.8seconds
g = 9.8m/s^2
Get S
S = 7.8u + 1/2(9.8)(7.8)²
S = 7.8u + 298.116
350 = 7.8u + 298.116
7.8u = 350 - 298.116
7.8u = 51.884
u = 51.884/7.8
u = 6.65m/s
Hence the rock's horizontal velocity was 6.65m/s