1. D - sound travels the fastest through solids
2. 50 mm/s - v=fa
3. B - only process that involves changing waves
You pick up the hula hoop and stand inside of it then pick it up will you’re inside it and hold to your waist and spin it then turn your hips
A ball would be something that floats in warter
Answer:
The electric field due to the right ring at a location midway between the two rings is 
Explanation:
Given that,
Radius of first ring = 5 cm
Radius of second ring = 20 cm
Charge on the left of the ring = +30 nC
Charge on the right of the ring = -30 nC
We need to calculate the electric field due to the right ring at a location midway between the two rings
Using formula of electric field
Put the value into the formula


Hence, The electric field due to the right ring at a location midway between the two rings is 