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Crank
3 years ago
9

a 6-kg and a 4-kg ball are acted on by forces of equal size. if the large ball accelerates at 2 m/s2 what acceleration will the

small ball undergo
Physics
2 answers:
Dennis_Churaev [7]3 years ago
5 0
To answer this question, we need to find the force acting on the two objects.

f=ma
f=(6)(2)
f=12 newtons

So, now we can determine the acceleration of the second object using the same formula!

f=ma
12=(4)a
3=a

So the acceleration of the smaller object is 3 meters per second squared!
Anna007 [38]3 years ago
3 0

It would be 30 meters.

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On February 15, 2013, Asteroid 2012 DA14 passed within 17,200 miles [mi] of the surface of the Earth at a relative speed of 7.8
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Answer:

The total amount of energy that would have been released if the asteroid hit earth = The kinetic energy of the asteroid = 1.29 × 10¹⁵ J = 1.29 PetaJoules = 1.29 PJ

1 PJ = 10¹⁵ J

Explanation:

Kinetic energy = mv²/2

velocity of the asteroid is given as 7.8 km/s = 7800 m/s

To obtain the mass, we get it from the specific gravity and diameter information given.

Density = specific gravity × 1000 = 3 × 1000 = 3000 kg/m³

But density = mass/volume

So, mass = density × volume.

Taking the informed assumption that the asteroid is a sphere,

Volume = 4πr³/3

Diameter = 30 m, r = D/2 = 15 m

Volume = 4π(15)³/3 = 14137.2 m³

Mass of the asteroid = density × volume = 3000 × 14137.2 = 42411501 kg = 4.24 × 10⁷ kg

Kinetic energy of the asteroid = mv²/2 = (4.24 × 10⁷)(7800²)/2 = 1.29 × 10¹⁵ J

6 0
3 years ago
A 57.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 120 kg football players at a height of 1.10 m. If her pisto
lapo4ka [179]

Answer:

The diameter of the piston of the players equals 55.136 cm.

Explanation:

from the principle of transmission of pressure in a hydraulic lift  we have

\frac{F_{1}}{A_{1}}=\frac{F_{2}}{A_{1}}

Since the force in the question is the weight of the individuals thus upon putting the values in the above equation we get

\frac{57.0\times 9.81}{\frac{\pi \times (19.0)^{2}}{4}}=\frac{4\times 120\times 9.81}{\frac{\pi \times D_{2}^{2}}{4}}

Solving for D_{2} we get

D_{2}^{2}=\frac{4\times 120}{57}\times 19^{2}\\\\\therefore D_{2}=\sqrt{\frac{4\times 120}{57}}\times 19\\\\D_{2}=55.136cm

5 0
3 years ago
Which of the following could be a step in a plan designed to mitigate the negative impacts of a natural hazard? I. design new te
erastova [34]
Designing warning and evacuation systems could be a step in a plan designed to mitigate the negative impacts of a natural hazard.
7 0
3 years ago
Read 2 more answers
A circuit has a 10 Ω resistor connected to a 1.5 V dry cell. What is the current that can flow in the circuit?
ludmilkaskok [199]

Here is the highly detailed, arcane, complex, technical form of Ohm's Law that is needed in order to answer this question  ===>  I = V / R  .

Current = (voltage) / (resistance)

Current = (1.5 V) / (10 Ω)

<em>Current = 0.15 Ampere</em>

8 0
3 years ago
Starting from the front door of your ranch house, you walk 50.0 m due east to your windmill, and then you turn around and slowly
Hunter-Best [27]

Answer:

Average velocity

v=\frac{d}{t}\\ v=\frac{10m}{70s}\\v=.1428 \frac{m}{s}

Average speed,

S=\frac{D}{t}\\ S=\frac{90}{70}\\ S=1.29\frac{m}{s}

Explanation:

(a)Average velocity

We have to find the average velocity. We know that velocity is defined as the rate of change of displacement with respect to time.

To find the average velocity we have to find the total displacement.

since displacement along east direction is 50m

and displacement along west=40m

so total displacement,

d=50m-40m\\d=10m

total time,

t=28 s+42 s\\t=70 s

therefore, average velocity

v=\frac{d}{t}\\ v=\frac{10m}{70s}\\v=.1428 \frac{m}{s}

(b)Average Speed:

Average speed is defined as the ratio of total distance to the total time

it means

Average speed= total distance/total time

here total distance,

D= 50m+40m\\D=90m

and total time,

t= 28s+40s\\t=70s

therefore,

Average speed,

S=\frac{D}{t}\\ S=\frac{90}{70}\\ S=1.29\frac{m}{s}

8 0
3 years ago
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