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Crank
3 years ago
9

a 6-kg and a 4-kg ball are acted on by forces of equal size. if the large ball accelerates at 2 m/s2 what acceleration will the

small ball undergo
Physics
2 answers:
Dennis_Churaev [7]3 years ago
5 0
To answer this question, we need to find the force acting on the two objects.

f=ma
f=(6)(2)
f=12 newtons

So, now we can determine the acceleration of the second object using the same formula!

f=ma
12=(4)a
3=a

So the acceleration of the smaller object is 3 meters per second squared!
Anna007 [38]3 years ago
3 0

It would be 30 meters.

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1. An asphalt block has a mass of 90 kg and a volume of 0.075 m. Determines the density of the asphalt.
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Answer:

1. Density = 1200[kg/m^3]; 2. Volume= 0.005775[m^3], mass= 15.59[kg]

Explanation:

1. We know that the density is defined by the following expression.

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2. First we need to convert the units to meters.

wide = 35[cm] = 35/100 = 0.35[m]

long = 11 [dm] =  11 decimeters = 11/10 = 1.1[m]

Thick = 15[mm] = 15/1000 = 0.015[m]

Now we can find the density using the expression for the density.

density= \frac{mass}{volume} \\where:\\volume = wide*long*thick\\volume=0.35*1.1*0.015 = 0.005775[m^3]\\\\mass= density*volume = 2700*0.005775 = 15.59[kg]

7 0
3 years ago
One beam of electrons moves at right angles to a magnetic field. the force on these electrons is 4.9 x 10-14 newtons. a second b
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A. (4.9 × 10-14 newtons) · tan(30°) 
<span>B. (4.9 × 10-14 newtons) · sin(30°) </span>
<span>C. (4.9 × 10-14 newtons) · cos(30°) </span>
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7 0
3 years ago
A torsional pendulum consists of a disk of mass 450 g and radius 3.5 cm, hanging from a wire. If the disk is given an initial an
Montano1993 [528]

To solve this problem we will use the kinematic equations of angular motion, starting from the definition of angular velocity in terms of frequency, to verify the angular displacement and its respective derivative, let's start:

\omega = 2\pi f

\omega = 2\pi (2.5)

\omega = 5\pi rad/s

The angular displacement is given as the form:

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In the equlibrium we have to t=0, \theta(t) = \theta_0 and in the given position we have to

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Derived the expression we will have the equivalent to angular velocity

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Replacing,

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Finally

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Therefore the maximum angular displacement is 9.848°

6 0
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