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Orlov [11]
3 years ago
14

A sample of ascorbic acid (vitamin C) is synthesized in the laboratory. It contains 1.50 g of carbon and 2.00 g of oxygen. Anoth

er sample of ascorbic acid isolated from citrus fruits contains 6.25 g of carbon.?
Physics
1 answer:
Karo-lina-s [1.5K]3 years ago
6 0

Answer:

8.467 gm

Explanation:

The law governing this problem is "The Law of Constant Composition "

As per this law, all compounds irrespective of their origin and source have the same composition and properties  in their purest form

It is a simple proportion and ratio related problem.

1.50 grams of carbon require 2.0 grams of oxygen

1.0 grams of carbon will require oxygen

=\frac{2}{1.5}

6.35 grams of carbon will require oxygen

\frac{2}{1.5}\times6.35= 8.4666\\= 8.467

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Vlada [557]

1.) equal volume of different substances have "different" masses.

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3.)the SI unit of power is "Watts".

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5.)balloons used for advertisements are filled with " helium" gas.

6.)"Conduction" is the primary mode of heat transfer in liquid and gases.

I hope this helps you...

5 0
3 years ago
If an exit sign is hanging from the ceiling by three chains each of which has a tension of 15N what is the weight of the sign
kvasek [131]
The weight is 45 N, because the three chains hold the sign, and each contributes 15 N.

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3 0
4 years ago
When a cannon fires a cannonball, the cannon will recoil backward because the:
gulaghasi [49]

C) total linear momentum of the ball and cannon is conserved.

Basically it happens that in the beginning before there is a momentum acting on the two bodies, these are a unique system. Here the total momentum of the System is 0. However, when the positive momentum of the cannonball is added, the system will be immediately affected by a negative momentum which will pull back the cannon. Could this be extrapolated as a condition of Newton's third law.

4 0
3 years ago
Boyle’s Law: When____ is held constant, the pressure and volume of a gas are___ proportional.
Aleksandr-060686 [28]

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7 0
3 years ago
A circular dartboard has a radius of 2 meters and a red circle in the center. Assume you hit the target at a random point. For w
Sati [7]

Answer:

1.549 m

Explanation:

Given:

The radius of the circular board, r = 2 m

The probability of hitting the red is given as 0.6

Now, this probability of hitting the red can be conclude as

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let the radius of the red area be R

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on substituting the value of the area, we have

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or

R² = 2.4

or

R = 1.549 m

Thus, the radius of the red circle is 1.549 m

3 0
3 years ago
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