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3 years ago

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A sample of ascorbic acid (vitamin C) is synthesized in the laboratory. It contains 1.50 g of carbon and 2.00 g of oxygen. Anoth

er sample of ascorbic acid isolated from citrus fruits contains 6.25 g of carbon.?

1 answer:

Karo-lina-s [1.5K]3 years ago

6 0

Answer:

8.467 gm

Explanation:

The law governing this problem is "The Law of Constant Composition "

As per this law, all compounds irrespective of their origin and source have the same composition and properties in their purest form

It is a simple proportion and ratio related problem.

1.50 grams of carbon require 2.0 grams of oxygen

1.0 grams of carbon will require oxygen

= $\frac{2}{1.5}$

6.35 grams of carbon will require oxygen

$\frac{2}{1.5}\times6.35$ = 8.4666\\= 8.467

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The density, hard, strong, and rough.

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A 1400-kg car is traveling with a speed of 17.7 m/s. What is the magnitude of the horizontal net force that is required to bring

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Answer:

The magnitude of the horizontal net force is 13244 N.

Explanation:

Given that,

Mass of car = 1400 kg

Speed = 17.7 m/s

Distance = 33.1 m

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Using equation of motion

$v^2-u^2=2as$

Where, u = initial velocity

v = final velocity

s = distance

Put the value in the equation

$0-(17.7)^2=2a\times 33.1$

$a=\dfrac{-(17.7)^2}{33.1}$

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We need to calculate the net force

Using newton's formula

$F = ma$

$F =1400\times(-9.46)$

$F=-13244\ N$

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A 2.26 kg book is dropped from a height 1.5m what is its acceleration

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What is the magnitude of the torque about his shoulder due to the weight of the ball and his arm if he holds his arm straight ou

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Answer:

The torque about his shoulder is 34.3Nm.

The solution approach assumes that the weight of the boy's arm acts at the center of the boy's arm length 35cm from the shoulder.

Explanation:

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A cube 6.0 cm on each side is made of a metal alloy. After you drill a cylindrical hole 2.0 cm in diameter all the way through a

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To solve this problem it is necessary to apply the concepts related to Newton's second law, the definition of density and the geometric relationships that allow us to find the volume of the figures presented.

For the particular case of the Cube with equal sides its volume is determined by

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$V_c = 6^3 = 216cm^3$

In the case of perforated material we have that its volume is given according to the cylindrical geometry, that is to say

$V_d = \pi r^2*l$

$V_d = \pi (\frac{2}{2})^2*6$

$V_d = 6\pi cm^3$

In this way the net volume would be

$\Delta V = V_c-V_d$

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$\rho = \frac{0.673}{197.15*10^{-6}}$

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3 years ago