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Orlov [11]
2 years ago
14

A sample of ascorbic acid (vitamin C) is synthesized in the laboratory. It contains 1.50 g of carbon and 2.00 g of oxygen. Anoth

er sample of ascorbic acid isolated from citrus fruits contains 6.25 g of carbon.?
Physics
1 answer:
Karo-lina-s [1.5K]2 years ago
6 0

Answer:

8.467 gm

Explanation:

The law governing this problem is "The Law of Constant Composition "

As per this law, all compounds irrespective of their origin and source have the same composition and properties  in their purest form

It is a simple proportion and ratio related problem.

1.50 grams of carbon require 2.0 grams of oxygen

1.0 grams of carbon will require oxygen

=\frac{2}{1.5}

6.35 grams of carbon will require oxygen

\frac{2}{1.5}\times6.35= 8.4666\\= 8.467

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A 25kg chair initially at rest on a horizontal floor requires a 165 N horizontal force to set it in motion. Once the chair is in
SCORPION-xisa [38]

Answer:

\mu_k=0.51  

Explanation:

Given that

Mass , m = 25 kg

We know that when body is in rest condition then static friction force act on the body and when body is in motion the kinetic friction force act on the body .That is why these two forces are given as follows

Static friction force ,fs= 165 N

Kinetic friction force ,fk = 127 N

If the body is moving with constant velocity ,it means that acceleration of that body is zero and all the forces are balanced.

Lets take coefficient of kinetic friction  = μk

The kinetic friction is given as follows

fk = μk  m g

Now by putting the values

127 = μk x 25 x 9.81

\mu_k=\dfrac{127}{25\times 9.81}

\mu_k=0.51

Therefore the value of coefficient of kinetic friction will be 0.51

4 0
2 years ago
Consider a spherical capacitor with radius of the inner conducting sphere a and the outer shell b. The outer shell is grounded (
AleksAgata [21]

Answer:

Explanation:

The application of Gauss's law is used in the derivation as shown with detailed step by step in the attached file.

The potential difference on this spherical capacitor is ΔV = Va - Vb = kQ/a - kQ/b = kQ(1/a - 1/b)

6 0
3 years ago
HELPPP!!!! WILL MARK BRAINLIEST
Harlamova29_29 [7]

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jek_recluse [69]

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If a person weighs 1000 N on the surface of the Earth, how much will they weigh on the surface of the Moon? What “g” value shoul
Dafna1 [17]

Answer:

Hence the weight of the person on the moon is 162.4, and the value of g used is 1.624 m/s²

Explanation:

from the question,

W = mg........................ Equation 1

Where W = weight of the man on Earth, m = mass of the man, g = acceleartion due to gravity of the man

make m the subject of the equation

m = W/g.............. Equation 2

Given: W = 1000 N,

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