Answer:68.15m/s
Explanation:
<u><em>Given: </em></u>
v₁=15m/s
a=6.5m/s²
v₁=?
x=340m
<u><em>Formula:</em></u>
v₁²=v₁²+2a (x)
<u>Set up:</u>
=
<h2><u><em>
Solution:</em></u></h2><h2><u><em>
68.15m/s</em></u></h2>
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Answer:
<em>When a balloon deflates air moves out of the balloon </em><em>because the pressure inside the balloon is higher than the pressure outside the balloon.</em>
Explanation:
An inflated balloon has a high pressure region on its inside. Gases always move from a region of high pressure to a region of low pressure. When a balloon is inflated its membrane stretches making it even more porous.
The gas molecules inside the balloon easily diffuse out through this membrane. The diffusion rate may differ depending on the type of gas filled inside the balloon and the material of the balloon. For example helium balloon deflates faster than common air balloon.
This is because helium is a light element and can escape easier than gases like nitrogen and oxygen through the porous membrane of the balloon.
Answer:
D. It represents a very large, complex system.
Explanation:
I just did it on a p e x...
Refer to the diagram shown below.
F = the minimum force required for opening the lid
r = 8.9/2 = 4.45 cm = 0.0445 m
P = the applied force, aplied at a distance of 13 cm = 0.13 m.
Because the required torque is 7.5 N-m, therefore
(0.13 m)*(P N) = 7.5 N-m
P = 57.6923 N
The equation for the lever requires that
0.13P = 0.0445F = 7.5
Therefore
F = 7.5/.0445 = 168.54 N
Answer: 168.5 N