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Murrr4er [49]
2 years ago
12

A skydiver is in free fall. What is the only force acting upon the skydiver.

Physics
1 answer:
sammy [17]2 years ago
4 0
I believe the forces acting are gravity and friction
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For a star with a parallax angle of 1/2 of an at arcsecond, what will be its distance in parsec?
avanturin [10]

(1 parsec) is the distance at which an object has a parallax of 1 arcsecond. The distance is about 3.26 light years.

Another way to understand it is:  The distance from which the Earth's orbit appears 1 arcsecond across.

For a parallax angle of 1/2 arcsecond, the distance is <em>2 parsecs </em>(about 6.52 light years).

1 arcsecond is 1/3600 of a degree, 0.00028 degree.  

8 0
3 years ago
Which sentence in the passage can be used to conclude that Eris is a dwarf planet and not a planet?
Lelu [443]
Eris is slightly more massive than Pluto. However, both of them are smaller than Earth's Moon.
This should conclude that Eris is a dwarf planet.
3 0
2 years ago
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How would i solve these problems, nobody in my class understands and there is a substitute
drek231 [11]

find acceleration force divided by Mass

a=f/m

6 0
3 years ago
The net external force on a golf cart is 411 N north of tha cart has a total mass of 281 kg what is tha cart acceleration
Alisiya [41]

1.46m/s²

Explanation:

Given parameters:

Mass of cart = 281kg

Net external force = 411N

Unknown:

Acceleration of the cart = ?

Solution:

According to newton's second law " the net force on a car is the product of its mass and acceleration";

            Force = mass x acceleration

Since acceleration of the cart is unknown;

     Acceleration = \frac{force}{mass} = \frac{411}{281}

  Acceleration = 1.46m/s²

learn more:

Newton's laws brainly.com/question/11411375

#learnwithBrainly

8 0
3 years ago
 A cat is being chased by a dog. Both are running in a straight line at constant speeds. The cat has a head start of 3.8 m. The
Mars2501 [29]
In 6 secs, the dog covers-
S=vt
8.9*6 = 53.4 m.
In the same time, the cat covers, 53.4-3.8 = 49.6 m.
Thus, speed of the cat, v= s/t, 
= 49.6/6 = 8.267 m/s
7 0
3 years ago
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