Answer:10842.33m/s
Explanation:
F=qvBsine
V=f/(qBsine)
V=(3.5×10^-2)÷(8.4×10^-4×6.7×10^-3×sin35)
V=10842.33m/s
Answer:
A and C is about 12 cm away from each other.
Explanation:
Answer:
![30 N \cdot m](https://tex.z-dn.net/?f=30%20N%20%5Ccdot%20m)
Explanation:
The torque applied by a force can be calculated as
![\tau = F d sin \theta](https://tex.z-dn.net/?f=%5Ctau%20%3D%20F%20d%20sin%20%5Ctheta)
where
F is the magnitude of the force
d is the length of the arm
is the angle between the direction of the force and the arm
In this problem, we have
F = 15 N
d = 2.0 m
![\theta=90^{\circ}](https://tex.z-dn.net/?f=%5Ctheta%3D90%5E%7B%5Ccirc%7D)
Substituting into the equation, we find
![\tau = (15)(2.0) sin 90^{\circ}=30 N \cdot m](https://tex.z-dn.net/?f=%5Ctau%20%3D%20%2815%29%282.0%29%20sin%2090%5E%7B%5Ccirc%7D%3D30%20N%20%5Ccdot%20m)
Answer:
Video
Explanation:
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