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V125BC [204]
3 years ago
4

Ideally in a semiconductor, intrinsic energy energy level should be in the middle of the band gap. Estimate the position of the

intrinsic energy level (Ei) for intrinsic Ge at 300K, assuming the effective mass values for electrons and holes are me = 0.041m0 and mp = 0.28m0 , respectively.
Engineering
1 answer:
lbvjy [14]3 years ago
3 0

Answer:

The position of  intrinsic energy level (Ei) for intrinsic Ge at 300 K is at 0.024 eV above the middle band gap.

Explanation:

We know that

Fermi level of intrinsic semiconductor given as

E_i=\dfrac{E_c+E_v}{2}-\dfrac{KT}{2}\ ln\left(\dfrac{m_e}{m_p}\right)^{3/2}

KT = average thermal energy at 300 K = 0.026 eV

\dfrac{E_c+E_v}{2}-E_i=\dfrac{KT}{2}\ ln\left(\dfrac{m_e}{m_p}\right)^{3/2}

Now by putting the values

\dfrac{E_c+E_v}{2}-E_i=\dfrac{KT}{2}\ ln\left(\dfrac{m_e}{m_p}\right)^{3/2}

\dfrac{E_c+E_v}{2}-E_i=\dfrac{0.026}{2}\ ln\left(\dfrac{0.041m_0}{0.28m_0}\right)^{3/2}

\dfrac{E_c+E_v}{2}-E_i=-0.024

E_i=\dfrac{E_c+E_v}{2}+0.024

So the position of  intrinsic energy level (Ei) for intrinsic Ge at 300 K is at 0.024 eV above the middle band gap.

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The question is incomplete. The complete question is --

An aluminum rod is press fitted onto an aluminum collar. The collar has an inner radius of 1 cm and an outer radius of 2 cm. Given the rod has a diameter of 1.01 cm and the young's modulus of aluminum is 69 GPa, determine the following :

1. the interference value, i

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Solution:

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Outer radius of the collar = 12 cm

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1. So, the interference , i =0

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8 0
3 years ago
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Answer:

The description including its scope is presented throughout the section below.

Explanation:

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Answer:

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One number is wrong; they all lack units.

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Answer:

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