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PtichkaEL [24]
4 years ago
10

Which ratio is not equivalent to 5/3

Mathematics
1 answer:
Kazeer [188]4 years ago
7 0

4/3 I hope this helps

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If f(x) is a function and f(1) = 5, then which of the following could not be true?
DedPeter [7]

The choice a could not be true because the value of f(1) is already equal to 5. Therefore, the value of f(1) cannot be 1. This is one of the properties of a function that for every value of x, there should be only one corresponding value of y.

8 0
3 years ago
The vertices of a triangle are A(2,4),B(-1,-3),and C(3,6). Find the new vertices. Use the rule (x,y) >>>(x-3,y+5)to tra
Mama L [17]

Answer:

A(-1,9), B(-4,2) and C(0,11)

Step-by-step explanation:

The vertices of a triangle are A(2,4),B(-1,-3),and C(3,6).

To translate, we use the rule (x,y) >>>(x-3,y+5)

For Vertex A(2,4),

The new vertex is (2-3, 4+5)=(-1,9)

For Vertex B(-1,-3)

The new vertex is (-1-3,-3+5)=(-4,2)

For Vertex C(3,6)

The new vertex is (3-3,6+5)=(0,11)

After translation of Vertex A, B and C by the given rule, the new points are A(-1,9), B(-4,2) and C(0,11)

8 0
3 years ago
What is 143/15 simplified
V125BC [204]
\sf \frac{143}{15}=?

\sf{ 15 \times 9 = 135}

\sf{143- 135 = 8}

\sf{ \frac{143}{15} =  \frac{135+8}{15}  =  \frac{135}{135} +  \frac{8}{15}

\sf{ \frac{143}{15} =\boxed{\huge{ 9 \frac{8}{15} }}}
8 0
3 years ago
Read 2 more answers
Whats 2+2 User: whats 2.3 in a fraction
Sergio [31]
2 + 2 = 4.

2.3 \times \frac{10}{10} =\boxed{\bf{\frac{23}{10} =2\frac{3}{10}}}
5 0
3 years ago
Read 2 more answers
Consider the quadratic function f(x)=−x^2+x+30
yaroslaw [1]

Answer:

The smallest xx-intercept is x = -5

The largest xx-intercept is x = 6

The yy-intercept is y = 30.

Step-by-step explanation:

Given a quadratic function in the following format:

f(x) = ax^{2} + bx + c = 0, a \neq 0

The x-values of the x-intercepts are x_{1}, x_{2}, given by the following formulas.

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a}

x_{2} = \frac{-b - \sqrt{\bigtriangleup}}{2*a}

\bigtriangleup = b^{2} - 4ac

We have that:

f(x) = -x^{2} + x + 30

This is not in the format above. I will multiply by (-1), so we have:

f(x) = x^{2} - x - 30

So, a = 1, b = -1, c = -30

\bigtriangleup = b^{2} - 4ac = (-1)^{2} - 4*(1)*(-30) = 1 + 120 = 121

x_{1} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) + \sqrt{121}}{2(1)} = \frac{12}{2} = 6

x_{2} = \frac{-b + \sqrt{\bigtriangleup}}{2*a} = \frac{-(-1) - \sqrt{121}}{2(1)} = \frac{-10}{2} = -5

This means that

The smallest xx-intercept is x = -5

The largest xx-intercept is x = 6

The y-intercept is the value of f(x) when x = 0. So

f(x)=−x^{2}+x+30

f(0) = 30

The yy-intercept is y = 30.

5 0
3 years ago
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