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PtichkaEL [24]
4 years ago
10

Which ratio is not equivalent to 5/3

Mathematics
1 answer:
Kazeer [188]4 years ago
7 0

4/3 I hope this helps

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Help me!!!!!!!!!!! Help help help
kakasveta [241]

Answer:

5 × \frac{1}{100}

Step-by-step explanation:

4*100+2*10+3*1+6*\frac{1}{10}+x+9*\frac{1}{1000}=423.659\\4*100+2*10+3*1+6*0.1+x+9*0.001=423.659\\400+20+3+0.6+x+0.009=423.659\\423.609+x=423.659\\x=0.05\\\\50*\frac{1}{10}=5\\\\5*\frac{1}{100}=0.05\\\\50=50\\\\5*0.05=0.25

8 0
3 years ago
Find the area. plzz help​
12345 [234]

The square has a side length of 9.

The area of the full square would be 9^2 = 9 x 9 = 81 square cm.

The area of the triangle is 1/2 x 4 x 3 = 6 square cm.

The area of the shape = 81 -6 = 75 square cm.

6 0
3 years ago
What should I buy? A study conducted by a research group in a recent year reported that of cell phone owners used their phones i
Llana [10]

Answer:

The probability that seven or more of them used their phones for guidance on purchasing decisions is 0.7886.

<em />

Step-by-step explanation:

<em>The question is incomplete:</em>

<em>What should I buy? A study conducted by a research group in a recent year reported that 57% of cell phone owners used their phones inside a store for guidance on purchasing decisions. A sample of 14 cell phone owners is studied. Round the answers to at least four decimal places. What is the probability that seven or more of them used their phones for guidance on purchasing decisions? </em>

We can model this as a binomial random variable, with p=0.57 and n=14.

P(x=k)=\dbinom{n}{k} p^{k}q^{n-k}

a) We have to calculate the probability that seven or more of them used their phones for guidance on purchasing decisions:

P(x\geq7)=\sum_{k=7}^{14}P(x=k)\\\\\\

P(x=7)=\dbinom{14}{7} p^{7}q^{7}=3432*0.0195*0.0027=0.1824\\\\\\P(x=8) = \dbinom{14}{8} p^{8}q^{6}=3003*0.0111*0.0063=0.2115\\\\\\P(x=9) = \dbinom{14}{9} p^{9}q^{5}=2002*0.0064*0.0147=0.1869\\\\\\P(x=10) = \dbinom{14}{10} p^{10}q^{4}=1001*0.0036*0.0342=0.1239\\\\\\P(x=11) = \dbinom{14}{11} p^{11}q^{3}=364*0.0021*0.0795=0.0597\\\\\\P(x=12) = \dbinom{14}{12} p^{12}q^{2}=91*0.0012*0.1849=0.0198\\\\\\P(x=13) = \dbinom{14}{13} p^{13}q^{1}=14*0.0007*0.43=0.004\\\\\\

P(x=14) = \dbinom{14}{14} p^{14}q^{0}=1*0.0004*1=0.0004\\\\\\

P(x\geq7)=0.1824+0.2115+0.1869+0.1239+0.0597+0.0198+0.004+0.0004\\\\P(x\geq7)=0.7886

7 0
3 years ago
A group of students surveyed chose baseball and soccer as their favorite sport in the ratio 3:8
Anna [14]
3x-\ those\ who\ chose\ baseball\\8x-\ those\ who\ chose\ soccer\\\\&#10;a)\\3x+8x=132\\\\&#10;11x=132\ \ \ | divide\ by\ 11\\\\x=12\\\\&#10;8x=8*12=96\\\\&#10;96\ chose\ soccer.\\\\\&#10;b)\\8x=56\ \ \ | divide\ by\ 8\\\\x=7\\\\&#10;3x=3*7=21\\\\&#10;21\ chose\ baseball.
5 0
3 years ago
Solve by factoring:<br><br> 5x^2 + 19x + 12 = 0
Mariulka [41]

When solving polynomial equations, first set the equation

equal to zero, then check for a Greatest Common Factor.

Since there is no greatest common factor, this will make life a

little bit more difficult because we will have to factor the trinomial.

First, find all possible factors for constant term.

I have listed these in red below.

Make sure to reverse the factors since in each binomial,

the first term is different so we need to reverse the factors.

The factors of 5x² will just be 5x and z.

After finding factors for the constant and the leading

coefficient for your trinomial, we can eliminate some factors.

If you have an odd coefficient on the middle term,

you can eliminate any pairs of even factors.

So the group I crossed out in purple below will be eliminated.

Another strategy is to use factors a little closer together.

So I would go with the 4 and 3 group.

Surely enough, our trinomial does factor with the 4 and 3.

Now set the factored trinomial equal to 0.

Then use zero product property and you have your answer.

5 0
3 years ago
Read 2 more answers
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