Question

20.0 g of Nitrogen is produced when oxygen gas reacts with NO gas. 29.8 L of oxygen is required at STP to produce this 20.0 g of NO.
A.
True

B.
False

Answer 1

The statement is false as 85675 grams of nitrogen dioxide is produced instead of 20 grams.

Explanation:

Balance equation for the reaction:

2NO + $O_{2}$ ⇒ 2N$O_{2}$

Data given:

mass of nitrogen produced = 20 gram

mass of oxygen = 29.8 litres or 29800 grams

0xygen is the limiting reagent so,

number of moles of oxygen: (atomic mass of 1 mole 32 grams/mole

number of moles = $\frac{mass}{atomic mass of 1 mole}$

putting the values in the equation:

 =  $\frac{29800}{32}$

  = 931.5 moles

1 mole of oxygen reacts to give 2 moles of NO2

931.5 moles of oxygen will give x moles

$\frac{2}{1}$=$\frac{x}{931.5}$

1862.5 moles of NO2 produced

in grams

mass = number of moles x atomic mass

mass = 1862.5 x 46.00

          = 85675 grams

The statement is false as 85675 grams of nitrogen dioxide is produced instead of 20 grams as said in question.