Question

11. For a math homework assignment, Karla found the

Answer 1

Answer:

Option C. 12 by 15

Step-by-step explanation:

Let the length be L

Let the width be w

Area of rectangle = L x w

Perimeter of rectangular = 2 (L + w)

From the question given,

A = 180

P = 54

180 = L x w (1)

54 = 2(L + w) (2)

From equation (2),

54 = 2(L + w)

Divide both side by the 2

54/2 = L + w

27 = L + w

L = 27 — w (3)

Substituting the value of L into equation (1), we have:

180 = L x w

180 = w(27 — w)

180 = 27w — w^2

Rearrange the expression

w^2 — 27w + 180 = 0 (4)

Solving by factorization method:

Multiply the first term (i.e w^2) with the last term (i.e 180). This gives 180w^2. Now find two factors of 180w^2, such that their sum will result to the second (i.e —27w). These factors are —12w and —15w.

Now, substitute these factors (—12w and —15w) into equation (4)

w^2 — 27w + 180 = 0

w^2 — 12w —15w + 180 = 0

w(w — 12) — 15(w — 12) =0

(w — 12) (w — 15) = 0

w = 12 or w = 15.

Substituting the value of w into equation (3)

L = 27 — w

When w = 12

L = 27 — 12 = 15

When w = 15

L = 27 — 15 = 12

Since the length is longer than the width, the length is 15 and the width is 12.

Therefore the dimensions is 12 x 15